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jeyben [28]
3 years ago
14

Task 5:

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
8 0

Answer:

p=18x+4

a=20x^2+17x-63

a=1350

Step-by-step explanation:

Given:

l=5x-7

w=4x+9

Required:

Area of the rectangle=?

Perimeter of the rectangle=?

If x = 9 inches what is the area of the shape=?

Formula:

a=l*w

p=2(l+w)

Solution:

p=2(l+w)

p=2(5x-7)+2(4x+9)

p=10x-14+8x+18

p=10x+8x+18-14

p=18x+4

a=l*w

a=(5x-7)(4x+9)

a=20x^2+45x-28x-63

a=20x^2+17x-63

Area of the shape if x=9in

a=20x^2+17x-63

a=20(81)+17(9)-63

a=1620+153-63

a=1413-63

a=1350

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Answer:

Step-by-step explanation:

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Using a random number calculator I've chosen the first individual to be surveyed as number 57 after that you have to add k= 106 to know wich are the next individuals to be sampled:

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I hope it helps!

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Answer:

D

Step-by-step explanation:

our basic Pythagorean identity is cos²(x) + sin²(x) = 1

we can derive the 2 other using the listed above.

1. (cos²(x) + sin²(x))/cos²(x) = 1/cos²(x)

1 + tan²(x) = sec²(x)

2.(cos²(x) + sin²(x))/sin²(x) = 1/sin²(x)

cot²(x) + 1 = csc²(x)

A. sin^2 theta -1= cos^2 theta

this is false

cos²(x) + sin²(x) = 1

isolating cos²(x)

cos²(x) = 1-sin²(x), not equal to sin²(x)-1

B. Sec^2 theta-tan^2 theta= -1

1 + tan²(x) = sec²(x)

sec²(x)-tan(x) = 1, not -1

false

C. -cos^2 theta-1= sin^2

cos²(x) + sin²(x) = 1

sin²(x) = 1-cos²(x), our 1 is positive not negative, so false

D. Cot^2 theta - csc^2 theta=-1

cot²(x) + 1 = csc²(x)

isolating 1

1 = csc²(x) - cot²(x)

multiplying both sides by -1

-1 = cot²(x) - csc²(x)

TRUE

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