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KatRina [158]
3 years ago
14

The sum of two complementary angles is 90°. For one pair of complementary angles, the measure of the first angle is 15 less than

twice the measure of the second angle. Write a system of equations that can be used to determine the measure of the first angle, a, and the measure of the second angle, b.
Mathematics
2 answers:
steposvetlana [31]3 years ago
4 0

let 2nd angle = x

 then 1st angle = 2x-15

 then you have 90 = x + 2x-15

2x +x = 3x

 so now 90 = 3x-15

add 15 to each side

105=3x

x = 105/3 = 35

1st angle = 35 degrees

 2nd angle = 2(35) - 15 = 70-15 = 65


ludmilkaskok [199]3 years ago
4 0

Answer:

Measure of first angle = 65° and Measure of second angle = 35°

Step-by-step explanation:

Let measure of first angle be a and measure of second angle be b

Now, the measure of the first angle is 15 less than twice the measure of the second angle

⇒ a + 15 = 2b

⇒ a = 2b - 15

Now, sum of two complementary angles is 90

⇒ a + b = 90

⇒ 2b - 15 + b = 90

⇒ 3b - 15 = 90

⇒ 3b = 105

⇒ b = 35

And a = 65

Therefore, Measure of first angle = 65° and Measure of second angle = 35°

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The revenue for a company producing widgets is given by y = -20x2 - 50x + 200, where x is the price in dollars for each widget.
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Answer:

The  price is   x =  $2.779

Step-by-step explanation:

From the question we are told that

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Generally at break even point the cost of production is equal to the  revenue

So

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6 0
3 years ago
Read 2 more answers
a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s
slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane  so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So,   w  = k V , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h  distance,  pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is,   V= \frac{1}{3}  *A* 5

So, weight of original pyramid,  W = k *(\frac{1}{3}  *A* 5) = 800

Volume of small pyramid is,  v = \frac{1}{3}* a* h

So, weight of small pyramid, w = k*(\frac{1}{3}* a* h)=400

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So,  \frac{a}{A}  = (\frac{h}{5}) ^{2}

       a = (\frac{h}{5} )^{2}A

Substituting value of a in  equation k*(\frac{1}{3}* a* h)=400

So, k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400

       (k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400

Since, (k *\frac{1}{3}  *A* 5) = 800, substitute in above equation.

    So, 800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet

Learn more:

brainly.com/question/17950304

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