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3 years ago

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The surface areas of two similar figures are 25in^2 and 36in^2. If the volume of the smaller figure is 250in^3, what is the volu

me of the larger figure?

1 answer:

Strike441 [17]3 years ago

3 0

What you would do is add 25in^2 and 36in^2 together to get your answer. thanks for asking a question I could answer.

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3 years ago

The function d =

Nuetrik [128]

Answer:

continuous

Step-by-step explanation:

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2 years ago

PLEASE HELP NTH TERM MATHS

fredd [130]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

You cut a piece of paper in half to get 1/4 of the paper. You repeat this four more times.

faust18 [17]

Answer:

The answer is 1/64

Step-by-step explanation:

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3 years ago

During the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this

alex41 [277]

Answer:

Step-by-step explanation:

Given that during the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this period, P(t) remained close to the solution of the initial value problem.

$\frac{dP}{dt} =0.03135P =0.0001489P^2, P(0) = 3.9$

a) 1930 population is the population at time t = 40 years taking base year as 40

We can solve the differential equation using separation of variables

$\frac{dP}{0.03135P – 0.0001489P^2 } =dt\\\frac{dP}{-P(0.03135 – 0.0001489P } =dt$

Resolve into partial fractions

$\frac{31.8979}{P} -\frac{0.00474}{0.0001489P-0.03135}$

Integrate to get

ln P -0.00474/0.0001489 (ln (0.0001489P-0.03135) = t+C

ln P -31.833 (ln (0.0001489P-0.03135) =t+C

$\frac{P}{( ( (0.0001489P-0.03135)^{31.833} } =Ae^t$

Limiting population would be infinity.

6 0

3 years ago