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3 years ago

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The surface areas of two similar figures are 25in^2 and 36in^2. If the volume of the smaller figure is 250in^3, what is the volu

me of the larger figure?

1 answer:

Strike441 [17]3 years ago

3 0

What you would do is add 25in^2 and 36in^2 together to get your answer. thanks for asking a question I could answer.

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A driveway 18 ft wide and 36 ft. long is to be paved with concrete 3 in. thick. How many cubic yards of concrete are required?

amm1812

Answer:

6 yds^3

Step-by-step explanation:

I find these easiest if you put all of the dimensions into yards and then multiply

18 ft = 6 yds

36 ft = 12 yds

3 in = 3/36 yds = 1/12 yds now multiply them together

6 x 12 x 1/12 = 6 yds^3

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2 years ago

C. If one cubic foot contains about 7.5 gallons, how many gallons of water are in the pool? (3 points) I Water: gallons 3. A rec

Dominik [7]

Answer:

<u>One Rectangular Pan</u>

Step-by-step explanation:

Part C cannot be answered since the dimensions of the pool are not given. Please check the question.

The cake pans may be compared by calculating the volume of each shape:

Rectangular pan: Volume = Length x Width x Height

Volume Rectangle = (13")*(9")*(2") = <u>234 in^3</u>

Round pan: Volume = $\pi r^{2} h$

Volume Round = (3.14)*(4")^2(2") = 100.5 in^3

Two round pans will hold 2*(100.5 in^3) or 201 in^3 of batter

One rectangular pan holds 234 in^3.

Go with the rectangular pan if you want more cake.

4 0

1 year ago

Mr. Gill is draining his pool. The pump he is using changes the water level by −2 1/4 inches per hour. A stronger pump would dra

professor190 [17]

Answer:

-5.625 in/hour

Step-by-step explanation:

−2 1/4 * 2 1/2 = -5.625 in/hour

7 0

3 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

so

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

so

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

NEED HELP PLEASE!!! Please explain your answer!

Zanzabum

<span> You must make it a fraction by multiplying by 100, moving the decimal over by 2 spaces right so we have 36. Then, put it over 100, because it is a fraction. Now, with 36/100 we must simplify by dividing each number by another # that goes into it evenly, such as 2. We get 18/50, reduce by 2, we get 9/25. There you go hope I helped </span>

7 0

2 years ago

Read 2 more answers