The true statement about the triangle is (a) b^2 + c^2 > a^2
<h3>How to determine the true inequality?</h3>
The sides are given as:
a, b and c
The angle opposite of side length a is an acute angle
The above means that:
The side a is the longest side of the triangle.
The Pythagoras theorem states that:
a^2 = b^2 + c^2
Since the triangle is not a right triangle, and the angle opposite a is acute.
Then it means that the square of a is less than the sum of squares of other sides.
This gives
a^2 < b^2 + c^2
Rewrite as:
b^2 + c^2 > a^2
Hence, the true statement about the triangle is (a) b^2 + c^2 > a^2
Read more about triangles at:
brainly.com/question/2515964
#SPJ1
Answer:
p = 8
Step-by-step explanation:
Let one root of the eqn. be alpha . Other root is 1/alpha .
We know that product of both roots of an quadratic eqn. is c/a where "c" is the co-efficient of the constant & "a" is the co-efficient of x^2.
Here "c" is p-4 & "a" is 4. And the product of roots is 1 ( ∵ prdouct of a number and its reciprocal is 1 )
Answer:
30 = 9x + 7
Step-by-step explanation:
The total weight of the bundle = 30 pounds
The weight of the bricks = x pounds
But he carried 9 bricks = 9x pounds
He also carried additional 7 pounds of concrete block.
An equation to show the total weight he carried is
30 pounds = (9x + 7) pounds
Since 9x represents the total weight of the bricks he carried
7 represents the weight of the concrete block
And 30 pounds represents the total weight of everything he carried.
I think the answer c is the right answer
