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777dan777 [17]
3 years ago
11

What is the slope-intercept form of a line

Mathematics
1 answer:
CaHeK987 [17]3 years ago
7 0
The first of the forms for a linear equation is slope-intercept form. Equations in slope-intercept form look like this: y = mx + b. where m is the slope of the line and b is the y-intercept of the line, or the y-coordinate of the point at which the line crosses the y-axis.

I Hope This Helps! (^_^)
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7 square yards is equal to how many square meters? A. 2.58 square meters B. 3.50 square meters C. 5.85 square meters D. 14.25 sq
love history [14]
5.85289 so C.

1 square yard is equal to 0.836127 square meters.
7 0
3 years ago
You invest $25/month at a rate of 3.25% APR compounded monthly for 30 years. What is the total interest earned and final balance
VikaD [51]

The total interest earned is 40.75 and the final balance is 65.75

<u>Solution:</u>

Given, principle amount P = 25

Interest rate r = 3.25\% = \frac{3.25}{100} = 0.0325

Times compounded per year n = 12

Time in years t = 30

Amount \ A=P\left(1+\frac{r}{n}\right)^{n t}

On substituting the values we get

A = 25 [ 1+ \frac{0.0325}{12}]^{12\times30}= 25 [2.63]= 65.75

Interest I = A - P [since, A = P+I]

\Rightarrow 65.75 - 25= 40.75

7 0
3 years ago
Find the solution of the system of equations. <br> 3x+3y= −6<br> 10x+3y= −13
Fittoniya [83]

Answer:

x=−1, y=−1

Step-by-step explanation:

Solve for x in the first equation.

x=−2−y

10x+3y=−13

Replace all occurrences of x with −2−y in each equation.

−20−7y=−13

x=−2−y

Solve for y in the first equation.

y=−1

x=−2−y

Replace all occurrences of y with −1 in each equation.

x=−1, y=−1

6 0
3 years ago
Which values are in the solution set of the compound inequality? Check all that apply. 4(x + 3) ≤ 0 or x + 1 &gt; 3 –6 –3 0 3 8
Colt1911 [192]

we have

4(x + 3) \leq 0 -------> inequality 1

or

x + 1 > 3 -------> inequality 2

we know that

In this system of inequalities, for a value to be the solution of the system, it is enough that it satisfies at least one of the two inequalities.

let's check each of the values

<u>case 1)</u> x=-6

<u>Substitute the value of x=-6 in the inequality 1</u>

4(-6 + 3) \leq 0

4(-3) \leq 0

-12 \leq 0 -------> is ok

The value of x=-6 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

<u>case 2)</u> x=-3

<u>Substitute the value of x=-3 in the inequality 1</u>

4(-3 + 3) \leq 0

4(0) \leq 0

0 \leq 0 -------> is ok

The value of x=-3 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

<u>case 3)</u> x=0

<u>Substitute the value of x=0 in the inequality 1</u>

4(0 + 3) \leq 0

4(3) \leq 0

12 \leq 0 -------> is not ok

<u>Substitute the value of x=0 in the inequality 2</u>

0 + 1 > 3

1 > 3 --------> is not ok

The value of x=0 is not a solution of the compound inequality

case 4) x=3

<u>Substitute the value of x=3 in the inequality 1</u>

4(3 + 3) \leq 0

4(6) \leq 0

24 \leq 0 -------> is not ok

<u>Substitute the value of x=3 in the inequality 2</u>

3 + 1 > 3

4 > 3 --------> is ok

The value of x=3 is a solution of the compound inequality

case 5) x=8

<u>Substitute the value of x=8 in the inequality 1</u>

4(8 + 3) \leq 0

4(11) \leq 0

44 \leq 0 -------> is not ok

<u>Substitute the value of x=8 in the inequality 2</u>

8 + 1 > 3

9 > 3 --------> is ok

The value of x=8 is a solution of the compound inequality

<u>case 6)</u> x=10

<u>Substitute the value of x=10 in the inequality 1</u>

4(10 + 3) \leq 0

4(13) \leq 0

52 \leq 0 -------> is not ok

<u>Substitute the value of x=10 in the inequality 2</u>

10+ 1 > 3

11 > 3 --------> is ok

The value of x=10 is a solution of the compound inequality

therefore

<u>the answer is</u>

[-6,-3,3,8,10]

7 0
3 years ago
For what non-zero value of x,
prisoha [69]

Answer:

  • d) 1/(4p²)

Step-by-step explanation:

<u>Let's complete the square first:</u>

  • p⁴ - 2p²x² + x⁴ + x =
  • p⁴ + 2p²x² + x⁴ - 4p²x² + x =
  • (p² + x²)² - (4p²x² - x)

<u>In order the expression above to be a perfect square, we need:</u>

  • 4p²x² - x = 0

<u>Solve it for x:</u>

  • 4p²x² = x
  • 4p²x = 1
  • x = 1/(4p²)

Correct choice is d

4 0
2 years ago
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