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3 years ago

What is the slope-intercept form of a line

1 answer:

7 0

The first of the forms for a linear equation is slope-intercept form. Equations in slope-intercept form look like this: y = mx + b. where m is the slope of the line and b is the y-intercept of the line, or the y-coordinate of the point at which the line crosses the y-axis.

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7 square yards is equal to how many square meters? A. 2.58 square meters B. 3.50 square meters C. 5.85 square meters D. 14.25 sq

love history [14]

5.85289 so C.

1 square yard is equal to 0.836127 square meters.

7 0

3 years ago

You invest $25/month at a rate of 3.25% APR compounded monthly for 30 years. What is the total interest earned and final balance

VikaD [51]

The total interest earned is 40.75 and the final balance is 65.75

Solution:

Given, principle amount P = 25

Interest rate $r = 3.25\% = \frac{3.25}{100} = 0.0325$

Times compounded per year n = 12

Time in years t = 30

$Amount \ A=P\left(1+\frac{r}{n}\right)^{n t}$

On substituting the values we get

$A = 25 [ 1+ \frac{0.0325}{12}]^{12\times30}= 25 [2.63]= 65.75$

Interest I = A - P [since, A = P+I]

$\Rightarrow 65.75 - 25= 40.75$

7 0

3 years ago

Find the solution of the system of equations. 3x+3y= −6 10x+3y= −13

Fittoniya [83]

Answer:

x=−1, y=−1

Step-by-step explanation:

Solve for x in the first equation.

x=−2−y

10x+3y=−13

Replace all occurrences of x with −2−y in each equation.

−20−7y=−13

x=−2−y

Solve for y in the first equation.

y=−1

x=−2−y

Replace all occurrences of y with −1 in each equation.

x=−1, y=−1

6 0

3 years ago

Which values are in the solution set of the compound inequality? Check all that apply. 4(x + 3) ≤ 0 or x + 1 > 3 –6 –3 0 3 8

Colt1911 [192]

we have

$4(x + 3) \leq 0$ -------> inequality 1

$x + 1 > 3$ -------> inequality 2

we know that

In this system of inequalities, for a value to be the solution of the system, it is enough that it satisfies at least one of the two inequalities.

let's check each of the values

case 1) x=-6

Substitute the value of x=-6 in the inequality 1

$4(-6 + 3) \leq 0$

$4(-3) \leq 0$

$-12 \leq 0$ -------> is ok

The value of x=-6 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

case 2) x=-3

Substitute the value of x=-3 in the inequality 1

$4(-3 + 3) \leq 0$

$4(0) \leq 0$

$0 \leq 0$ -------> is ok

The value of x=-3 is a solution of the compound inequality-----> It is not necessary to check the second inequality, because the first one satisfies

case 3) x=0

Substitute the value of x=0 in the inequality 1

$4(0 + 3) \leq 0$