The scores of 1000 students on a standardized test are normally distributed with a mean of 50 and a standard deviation of 5. wha
1 answer:
We are looking to find P(X>60 students)
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students
To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students
To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
You might be interested in
Answer:
An angle bisector divides the angle measure into two equal parts. In triangle ABC, B is the point at which the angle lies.
Step-by-step explanation:
Picture segment BD drawn from point B of tri.ABC where it connects to segment AC, creating point D. Now picture E drawn on the newly created segment DC where it connects to point B and down to point C. Here's a drawing to better show this:
It's bisecting the bisected angle ABC. So, 140/2 = 70, and 70/2 = 35.
