The scores of 1000 students on a standardized test are normally distributed with a mean of 50 and a standard deviation of 5. wha
1 answer:
We are looking to find P(X>60 students)
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students
To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
X is normally distributed with mean 50 and standard deviation 5
We need to find the z-score of 60 students
To find the probability of P(Z>2), we can do 1 - P(Z<2)
So we read the probability when Z<2 which is 0.9772, then subtract from one we get 0.0228
The number of students that has score more than 60 is 0.0228 x 1000 = 228 students
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Answer:
Fred would take 33 days to save $ 70.95.
Step-by-step explanation:
The number of days () is directly proportional to the quantity of money saved (
), in monetary units, then we can calculate the time taken to save $ 70.95 by simple rule of three:
Fred would take 33 days to save $ 70.95.
We can compare by converting Johnny's reading time into the same unit of Jacky's, hours.
There are 60 minutes in an hour, so use this:
15 < 20, so Johnny read faster. This is 5 pages faster per hour than Jacky.
There are 60 minutes in an hour, so use this:
15 < 20, so Johnny read faster. This is 5 pages faster per hour than Jacky.