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kherson [118]
3 years ago
11

The product of a rational number and an integer is not an integer. True or false?

Mathematics
1 answer:
labwork [276]3 years ago
3 0
False
An example of the product of a rational number and an integer that is an integer.
1/2 × 8= 4
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The sum of a number and its square is 182. Find the number.
Mars2501 [29]

Answer:

13 and -14 satisfy this condition

Step-by-step explanation:

Let's represent that number as x

and the square of x is x^2

So,

x + x^2 = 182

Subtract 182 from both sides

x + x^2 - 182 = 182 - 182

x + x^2 - 182 = 0

rearrange the quadratic equation

x^2 + x -182 = 0

let's use the quadratic formula

\frac{-b+\sqrt{b^2-4ac} }{2a}       or      \frac{-b-\sqrt{b^2-4ac} }{2a}

a = 1, b = 1, c = -182

\frac{-1+\sqrt{1^2-4*1*(-182)} }{2*1}       or     \frac{-1-\sqrt{1^2-4*1*(-182)} }{2*1}

\frac{-1+\sqrt{1+728} }{2}      or         \frac{-1-\sqrt{1+728} }{2}

\frac{-1+\sqrt{729} }{2}            or    \frac{-1-\sqrt{729} }{2}

\frac{-1+{27} }{2}     or    \frac{-1-{27} }{2}

\frac{26}{2}     or    \frac{-28}{2}

13 or    - 14

Lets check

13 + 13^2 = 13 + 169

= 182

Also,

-14 + (-14^2) = -14 + 196

= 182

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Answer: the answer is 0.5

Step-by-step explanation:

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Which of the following is a statistical question
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