2) Solve the following equation for x: 2(x-5) = 36 A) 15.5 В) 23 С) 18 D) 13
2 answers:
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Answer:
Step-by-step explanation:
Hello!
The variable of interest is:
X: fitness of a line of E. coli grown on an acidic environment.
n= 6 E. coli lines
Recorded fitness for each line: 1.24, 1.22, 1.23, 1.24, 1.18, 1.09
The relative fitness of 1 indicates that both bacteria types are equally fit.
A relative fitness larger than 1 indicates that the acid-evolved line is more fit than the parental line kept at neutral pH when both are grown in acidic conditions.
Meaning that if the average fitness of the E. coli lines grown on an acidic environment is greater than 1 then they are better adjusted to live in acidic conditions, symbolically: μ > 1
The statistic hypotheses are:
H₀: μ ≤ 1
H₁: μ > 1
α: 0.05
Assuming that the variable has a normal distribution you have to apply a one-sample t-test:
X[bar]= 1.20
S= 0.06
The p-value for this test is 0.0002
Since the p-value= 0.0002 is less than α:0.05 the decision is to reject the null hypothesis.
Then at a 5% significance level, there is significant evidence to conclude that the bacteria evolved in acidic pH are better adapted to acidic conditions.
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Answer:
The number of cards Frank has is 18 and the number of cards his friend has is 24.
Step-by-step explanation:
<u><em>The correct question is </em></u>
Two friends are collecting cards. Frank has 6 more than half the number of cards as his friend. Together they have 42 cards. How many cards does each friend have?
Let
x ----> the number of cards that Frank has
y ----> the number of cards that his friend has
we know that
Together they have 42 cards
----> equation A
Frank has 6 more than half the number of cards as his friend
---> equation B
Solve the system by substitution
Substitute equation B in equation A
solve for y
<em>Find the value of x</em>
therefore
The number of cards Frank has is 18 and the number of cards his friend has is 24.