Compute: 3.5 x 2.4 x 0.01 <br><br><br><br> 0.84<br><br><br> 0.084<br><br><br> 0.0084

What does an isometric transformation do?

BaLLatris [955]

Answer:

Option: B is correct.

( Preserves the shape and size of the figure )

Step-by-step explanation:

An ISOMETRIC TRANSFORMATION (RIGID MOTION) is a transformation that preserves the distances and/or angles between the pre-image and image.
The isometric transformations are reflection, rotation and translation and combinations of them such as the glide, which is the combination of a translation and a reflection.

Hence, option B is correct.

Preserves the shape and size of the figure.

4 0

3 years ago

Read 2 more answers

If the sixth term of a sequence is 128 and the common ratio is 2, then what is the first term?

Lady bird [3.3K]

Geometric progresión:
we can calculate any term, using this rule:

an=a₁*r^(n-1)
a₁=the first term
r=the common ratio

a₆=128
r=2

an=a₁ * r^(n-1)
128=a₁ * 2⁶⁻¹
128=a₁ * 2⁵
128=a₁ * 32
a₁=128/32=4

Solution: a₁=4

3 0

3 years ago

A yo-yo is moving up and down a string so that its velocity at time t is given by v(t) = 3cos(t) for time t ≥ 0. The initial pos

jeka57 [31]

Part A - The average value of v(t) over the interval (0, π/2) is 6/π

Part B - The displacement of the yo-yo from time t = 0 to time t = π is 0 m

Part C - The total distance the yo-yo travels from time t = 0 to time t = π is 6 m.

<h3>Part A: Find the average value of v(t) on the interval (0, π/2)</h3>

The average value of a function f(t) over the interval (a,b) is

$f(t)_{avg} = \frac{1}{b - a} \int\limits^b_a {f(t)} \, dx$

So, since velocity at time t is given by v(t) = 3cos(t) for time t ≥ 0. Its average value over the interval (0, π/2) is given by

$v(t)_{avg} = \frac{1}{\frac{\pi }{2} - 0} \int\limits^{\frac{\pi }{2} }_0 {v(t)} \, dt$

Since v(t) = 3cost, we have

$v(t)_{avg} = \frac{1}{\frac{\pi }{2} - 0} \int\limits^{\frac{\pi }{2} }_0 {3cos(t)} \, dt\\= \frac{3}{\frac{\pi }{2}} \int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt\\= \frac{6}{{\pi}} [{sin(t)}]^{\frac{\pi }{2} }_{0} \\= \frac{6}{{\pi}} [{sin(\frac{\pi }{2})} - sin0]\\ = \frac{6}{{\pi}} [1 - 0]\\ = \frac{6}{{\pi}} [1]\\ = \frac{6}{{\pi}}$

So, the average value of v(t) over the interval (0, π/2) is 6/π

<h3>Part B: What is the displacement of the yo-yo from time t = 0 to time t = π?</h3>

To find the displacement of the yo-yo, we need to find its position.

So, its position x = ∫v(t)dt

= ∫3cos(t)dt

= 3∫cos(t)dt

= 3sint + C

Given that at t = 0, x = 3. so

x = 3sint + C

3 = 3sin0 + C

3 = 0 + C

C = 3

So, x(t) = 3sint + 3

So, its displacement from time t = 0 to time t = π is

Δx = x(π) - x(0)

= 3sinπ + 3 - (3sin0 + 3)

= 3 × 0 + 3 - 0 - 3

= 0 + 3 - 3

= 0 + 0

= 0 m

So, the displacement of the yo-yo from time t = 0 to time t = π is 0 m

<h3>Part C: Find the total distance the yo-yo travels from time t = 0 to time t = π. (10 points)</h3>

The total distance the yo-yo travels from time t = 0 to time t = π is given by

$x(t) = \int\limits^{\pi}_0 {v(t)} \, dt\\= \int\limits^{\pi }_0 {3cos(t)} \, dt\\= 3 \int\limits^{\pi }_0 {cos(t)} \, dt\\ = 3 \int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt + 3\int\limits^{\pi }_{\frac{\pi }{2}} {cos(t)} \, dt\\= 3 \times 2\int\limits^{\frac{\pi }{2} }_0 {cos(t)} \, dt\\= 6 [{sin(t)}]^{\frac{\pi }{2} }_{0} \\= 6[{sin\frac{\pi }{2} - sin0]\\\\= 6[1 - 0]\\= 6(1)\\= 6$

So, the total distance the yo-yo travels from time t = 0 to time t = π is 6 m.

Learn more about average value of a function here:

brainly.com/question/15870615

#SPJ1

4 0

1 year ago

PLZ HELP ASAP<br><br>!!!!!!

notsponge [240]

Answer:

m<A = 133

Step-by-step explanation:

Opposite angles of an inscribed quadrilateral are supplementary.

That means that m<A + m<C = 180.

m<A + m<C = 180

4x + 5 + x + 15 = 180

5x + 20 = 180

5x = 160

x = 32

m<A = 4x + 5

m<A = 4(32) + 5

m<A = 128 + 5

m<A = 133

7 0

3 years ago

How to convert the equation<br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7Bq%7D%7B5%20%7B%7D%5E%7Bx%7D%20%7D%20" id

polet [3.4K]

Answer:

$xlog 5 = logq - log y\\$

Step-by-step explanation:

Given the equation $y = \frac{q}{5^{x} }$ , to convert to linear form, the following steps must be followed;

$5^{x} = \frac{q}{y}\\ y5^{x} = q\\taking\ the\ log\ of\ both\ sides\\log(y5^{x}) = log q\\logy + log 5^{x} = log q\\log y + xlog5 = log q\\xlog 5 = logq - log y\\$

The final expression is a linear form of the expression

8 0

4 years ago

Compute: 3.5 x 2.4 x 0.01 0.84 0.084 0.0084