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3 years ago

11

How is the process of rewriting literal equations similar to the process of solving equations in one variable? How is it differe

nt?

1 answer:

Scilla [17]3 years ago

8 0

U don't answer the question just leave it

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The volume of a cone is one-third the volume of which type of solid? Question 4 options: prism pyramid cylinder sphere

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Answer: Cylinder

Step-by-step explanation:

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How do to improper fraction

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2d+7/6-d-5/3=0 Tell me the answer

Inessa [10]

Answer:

d=1／2

Step-by-step explanation:

$2d + \frac{7}{6} - d - \frac{5}{3} = 0 \\ 2d - d = \frac{5}{3} - \frac{7}{6} \\ d = \frac{10}{6} - \frac{7}{6} \\ d = \frac{3}{6} \\ d = \frac{1}{2}$

3 0

3 years ago

Match the following items.

zaharov [31]

Answer:<1=63.5

<2= 124 = 34+90

<3= 29.5 =59/2

<4= 90

<5= 54 108/2

<6=116.5

<7=121. 53+68

Step-by-step explanation:

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3 years ago

Complete the following table for residuals for the exponential function: f(x) = 49.3(1.47)

agasfer [191]

Answer:

Predicted values:

$\hat y_1 = 49.3 (1.47)^1 =72.471$

$\hat y_2 = 49.3 (1.47)^2 =106.5324$

$\hat y_3 = 49.3 (1.47)^3 =156.6026$

$\hat y_4 = 49.3 (1.47)^4 =230.2058$

$\hat y_5 = 49.3 (1.47)^5 =338.4025$

$\hat y_6 = 49.3 (1.47)^6 =497.4517$

$\hat y_7 = 49.3 (1.47)^7 =731.254$

$\hat y_8 = 49.3 (1.47)^8 =1074.943$

Residuals:

$e_1 = 65-72.471=-7.471$

$e_2 = 90-106.5324=-16.5324$

$e_3 = 162-156.6026 = 5.3974$

$e_4 = 224-230.2058 = -6.2058$

$e_5 = 337-338.4025 = -1.4025$

$e_6 = 466-497.4617 = -31.4517$

$e_7 = 780-731.254 = 48.7459$

$e_8 = 1087-1074.493 = 12.0566$

Step-by-step explanation:

For this case we assume the following exponential function:

$\hat y_i = 49.3 (1.47)^x$

Where x represent the hours and y the predicted values for each hour. We can find the estimated values like this:

$\hat y_1 = 49.3 (1.47)^1 =72.471$

$\hat y_2 = 49.3 (1.47)^2 =106.5324$

$\hat y_3 = 49.3 (1.47)^3 =156.6026$

$\hat y_4 = 49.3 (1.47)^4 =230.2058$

$\hat y_5 = 49.3 (1.47)^5 =338.4025$

$\hat y_6 = 49.3 (1.47)^6 =497.4517$

$\hat y_7 = 49.3 (1.47)^7 =731.254$

$\hat y_8 = 49.3 (1.47)^8 =1074.943$

Now we can find the residuals with this formula:

$e_i = Y_i -\hat y_i$

And replacing we got:

$e_1 = 65-72.471=-7.471$

$e_2 = 90-106.5324=-16.5324$

$e_3 = 162-156.6026 = 5.3974$

$e_4 = 224-230.2058 = -6.2058$

$e_5 = 337-338.4025 = -1.4025$

$e_6 = 466-497.4617 = -31.4517$

$e_7 = 780-731.254 = 48.7459$

$e_8 = 1087-1074.493 = 12.0566$

6 0

3 years ago