It would be 3:00 pm in Boston

Recall that

Take it one piece at a time. For

, we can scale

by -5:

If we shift the argument by 1 and scale by -5, we have

so if we subtract this from

, we'll end up with

For the next piece, we can add another scaled and shifted step like

so that

For the last piece, we add one more term:

and so putting everything together, we get

:

Answer:
Step-by-step explanation:
2x - 2 = - 200
Bringing like terms on one side
2x = - 200 + 2 = - 198
2x = - 198
x = - 198/2 = - 99
Pairs, in this case, relates to a group of 2 or more. We have 6 friends. Let's call them A,B,C,D,E,F. This will allow us to make a [some sort of] combination tree:
1. ABC against DEF
2. ABD against CEF
3. ABE against CDF
4. ABF against CDE
5. ACD against BFE
6. ACE against BDF
7. ACF against BDE
8. ADE against BCF
9. ADF against BCE
10. AEF against BCD
I believe there are 12 combinations... I just can't think of the last 2 though.