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4 years ago

Please answer this correctly

Mathematics

1 answer:

expeople1 [14]4 years ago

4 0

Answer:

4 bags

Step-by-step explanation:

The way to read a step and leaf diagram is to consider the "stem" as the tens digit and "leaf" ans the ones digit.

So "0" in stem and "5" in leaf would be the number "05" or simply "5"

Also, "2" in stem and "4" in leaf would be the number "24"

When we have more numbers in leaf, they are basically different numbers. So lets list the numbers from stem-and-leaf plot:

5, 24, 30, 34, 65, 70, 74, 87, 90

The question asks for how many numbers are there LESS THAN 40?

the numbers less than 40 are:

5, 24, 30, 34

That is 4 numbers

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Would you measure walls using inches or yards

Aleksandr [31]

Yards because inches are too small walls are normally really long and wide and using inches wouldn't be wise in this case.

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3 years ago

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If a= 5-2 root 6 then find the value of root a - 1/root a

lozanna [386]

Answer:

2\sqrt2

Step-by-step explanation:

a=5-2√6 ...(1)

$\frac{1}{a}=\frac{1}{5-2 \sqrt{6} } \times\frac{5+2\sqrt{6} }{5+2\sqrt{6} } =\frac{5+2\sqrt{6}}{(5-2\sqrt{6})(5+2\sqrt{6})} =\frac{5+2\sqrt{6}}{5 ^2-(2\sqrt{6})^2} =\frac{5+2\sqrt{6}}{25-24} =5+2\sqrt{6}\\a+\frac{1}{a}=5-2\sqrt{6}+5+2\sqrt{6}=10$

$(\sqrt{a}-\frac{1}{\sqrt{a}})^2=(\sqrt{a})^2+(\frac{1}{\sqrt{a}})^2-2 \times \sqrt{a} \times \frac{1}{\sqrt{a}}=a+\frac{1}{a}-2=10-2=8\\\sqrt{a}-\frac{1}{\sqrt{a}}=\sqrt{8}=2\sqrt{2}$

5 0

4 years ago

Help plz:)))I’ll mark u Brainliest

DENIUS [597]

9514 1404 393

Answer:

x = 7

Step-by-step explanation:

We can write a proportion relating the short segment to the full length:

(x+1)/18 = 4/(4+5)

x +1 = 8 . . . . . . multiply by 18 and simplify

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3 0

3 years ago

which of the following expressions represent the number of distinguishable permutations of the letters of the word conclusion

LekaFEV [45]

Answer:

See explanation

Step-by-step explanation:

In most cases, we run into the problem of arranging objects that are repeated. This often occurs when we have a word that has repeated letters.

Let us recall that permutation deals with arrangements which are distinguishable.

Hence, for the word CONCLUSION, the number of distinguishable arrangements are;

10!/2!2!2!

3 0

3 years ago

Find the dimensions of the rectangle of maximum area with sides parallel to the coordinate axes that can be inscribed in the ell

Volgvan

Answer:

The answer is below

Step-by-step explanation:

Find the dimensions of the rectangle of maximum area with sides parallel to the coordinate axes that can be inscribed in the ellipse 4x² + 16y² = 16

Solution:

Given that the ellipse has the equation: 4x² + 16y² = 16

let us make x the subject of the formula, hence:

4x² + 16y² = 16

4x² = 16 - 16y²

Dividing through by 4:

x² = (16 - 16y²)/4

x² = 4 - 4y²

Taking square root of both sides:

$x=\sqrt{4-4y^2 }\\$

The points of the rectangle vertices is at (x,y), (-x,y), (x,-y), (-x,-y). Hence the rectangle has length and width of 2x and 2y.

The area of a rectangle inscribed inside an ellipse is given by:

Area (A) = 4xy

A = 4xy

$A=4(\sqrt{4-4y^2} )y\\\\A=4y\sqrt{4-4y^2}=4\sqrt{4y^2-4y^4} \\\\The\ maximum\ area\ of\ the\ rectangle\ is\ at\ \frac{dA}{dy}=0\\\\ \frac{dA}{dy}=4(\frac{4-8y^2}{\sqrt{4-4y^2} } )\\\\4(\frac{4-8y^2}{\sqrt{4-4y^2} } )=0\\\\4-8y^2=0\\\\8y^2=4\\\\y^2=1/2\\\\y=\frac{1}{\sqrt{2} }\\\\x=\sqrt{4-4(\frac{1}{\sqrt{2} })^2}=\sqrt{2}$

Therefore the length = 2x = 2√2, the width = 2y = 2/√2

7 0

3 years ago