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2 years ago

The sum of three consecutive even integer is 42. What is the value of the second largest integer

Mathematics

1 answer:

Naya [18.7K]2 years ago

5 0

Answer: 14
Explanation: x + x + 2 + x + 4 = 42. x = 12. 12 + 2 = 14. I don’t really know how to explain it on words

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becky has the addresses of many people listed in her email book . she forwarded a copy of an article to all 5 of those people. i

Marianna [84]

P = 5

I am not sure if this is correct. However, P is used to represent the addresses and there are 5 addresses. Therefore p = 5.

8 0

3 years ago

Identify all of the real fifth roots of 1024.

V125BC [204]

Answer:

Real fifth root of 1024 is 4.

Step-by-step explanation:

We have to find the value of real fifth root of 1024.

For this let fifth root of 1024 = x

Therefore $x^{5} = 1024 = 4^{5}$

Or $x^{5}=4^{5}$

Therefore x = 4

X= 4 is the right answer.

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3 years ago

Read 2 more answers

What answee is it?? :))))

Nataliya [291]

Step-by-step explanation:

The answer is C

We can easily eliminate B and D since Ms. Macdonald isn't starting with 3 rabbits.

We can also eliminate choice A, because 5 to the 3rd power isn't 15.

5 to the 3rd power is 125, therefore the choice is C

8 0

2 years ago

Read 2 more answers

A regression equation that predicts the price of homes in thousands of dollars is t = 24.6 + 0.055x1 - 3.6x2, where x2 is a dumm

AveGali [126]

Answer:

a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.

Step-by-step explanation:

For the same home (x1 is the same), x2 = 1 if it is on a busy street and x2 = 0 if it is not on a busy street. If x2 = 1, the value of 't' decreases by 3.6 when compared to the value of 't' for x2=0. Since 't' is given in thousands of dollars, when a home is on a busy street, its value decreases by 3.6 thousand dollars.

$t(x1, 0)= 24.6 + 0.055x1\\t(x1, 1) = 24.6 + 0.055x1 - 3.6\\t(x1, 1) = t(x1, 0) - 3.6$

Therefore, the answer is a) On average, homes that are on busy streets are worth $3600 less than homes that are not on busy streets.

8 0

3 years ago

If <img src="https://tex.z-dn.net/?f=t_n" id="TexFormula1" title="t_n" alt="t_n" align="absmiddle" class="latex-formula"> = 11n−

4vir4ik [10]

$\displaystyle\bf\\t_n=11n-6\\\\t_1=11\cdot1-6=11-6=\boxed{\bf5}\\\\t_{10}=11\cdot10-6=110-6=\boxed{\bf104}\\\\t_{n+1}-t_n=11(n+1)-6-(11\cdot n-6)=11n+11-6-11n+6=\boxed{\bf11}$

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3 years ago