All categories

2 years ago

The quoient of two numbers is a negitive.what must be true about the two numbers?

Mathematics

1 answer:

nikdorinn [45]2 years ago

5 0

Answer:

Step-by-step explanation:

When you divide a negative number by a positive number then the quotient is negative. When you divide a positive number by a negative number then the quotient is also negative.

You might be interested in

Which number is between 7.17 x 10^4 and 8.17 10^5 A. 6.92 x 10^4 B. 7.2 x10^9 C. 7.57 x 10^3 D. 8.053 x 10^4

Serga [27]

Answer:

D. 8.053 x 10^4

Step-by-step explanation:

Given :

7.17 x 10^4 and 8.17 10^5

The number in between the two Given numbers should be greater Than 7.17*10^4 but less than 8.17*10^5

A. 6.92 x 10^4 - this is less than 7.17 * 10^4 ; hence doesn't fit in

B. 7.2 x10^9 - this is greater than both values, hence, doesn't fit in

C. 7.57 x 10^3 - this is less than 7.17*10^4 ; hence does not fit in

D. 8.053 x 10^4 - this fits in as it is greater than 7.17*10^4 and less than 8.17*10^5 ; hence, it is the correct answer.

6 0

2 years ago

THIS IS MULTIPLE CHOICE!

Troyanec [42]

Answer:

there is a cluster from 1-4

there is a gap from 5-7

The spread is from 1-8

Step-by-step explanation:

These are all true if you look... there is a bunch from 1-4, there is none from 5-7, and all of them are within 1-8, but the highest amount isn't at 3.

7 0

2 years ago

G(a) = 4a ha)=a² + 2a Find (g - h)(a)

Reil [10]

Step-by-step explanation:

all work is shown and pictured

4 0

2 years ago

PLZ HELP, AND PLZ EXPLAIN

shutvik [7]

Answer:

Step-by-step explanation:

To make it easy let's start by organizing our information :

AC=12 AND BD=8
ABCD is a rhombus
K and L are the midpoints of sides AD and CD
we notice that the rhombus ABCD is divided into four right triangles

What do you think of when you hear a right triangle ?

The pythagorian theorem !

AC and BD are khown so let's focus on them .

If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?

Simply because they are the diagonals of a rhombus .

ow let's apply the pythagorian theorem :

(AC/2)² + (BD/2)² = BC²
6²+4²=52
BC²= 52⇒ $\sqrt{52}$ =BC

Now we khow that : AB=BC=CD=AD= $\sqrt{52}$

This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle

KL is parallel to AC
k is the midpoint of AD and L of DC

I smell something . yes! Thales theorem

KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE

KL/12= $\sqrt{52}$ /2* $\sqrt{52}$
KL/12=1/2⇒ KL=6

Now we have the length of the base kl

Now the big boss the height :

notice that you khow the length of KL
BD crosses kl from its midpoint and DL = $\sqrt{52}$ /2

What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D

DL²=(KL/2)²+D²
52/4= 9+ D²
D² = 52/4-9 +4 SO D=2

now the height of the trigle is H= BD-D= 8-2=6

NOw the area of the triangle is :

A=(KL*H)/2 ⇒ A= (6*6)/2=18

THE ANSWER IS 18 SQ.UN

5 0

2 years ago

Lalasa and yasmin are designing a triangular banner to hang in the school gymnasiums. They first draw the design on paper. The t

jasenka [17]

The triangle on paper is 5 inches wide by 7 inches high.

If 1 inch on paper is equal to 1.5 feet on paper, then you need to multiply all dimensions by 18 because 1.5 feet is equal to 18 inches and you are getting 18 inches on the real banner for every inch on the paper banner. 

5 * 18 = 90 inches from the base of the rear triangle.
7 * 18 = 125 inches for the height of the rear triangle. 
The area of the paper triangle will be 5 * 7 / 2 = 35/2 square inches.
The area of the rear triangle will be 90 * 125 / 2 = 5625 square inches. 

regarding feet:

The base of the real banner will be 125/12 = 10.41666666....... feet.
the height of the real banner will be 90 / 12 = 7.5 feet.
the area of the real banner will be 5625 / 12^1 = 5625 / 144 = 39.0625 square feet.

3 0

2 years ago