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son4ous [18]
3 years ago
5

Can someone help me in number 3 please

Mathematics
1 answer:
Sholpan [36]3 years ago
4 0

Area of rectangle is the multiplication between the sides.


The first rectangle:


A = (2x + 5) . (3x - 2)

A = 2x . 3x - 2 . 2x + 5 . 3x - 2 . 5

A = 6x² - 4x + 15x - 10

A = 6x² + 11x - 10


The second rectangle:


A = (5y + 5) . (2y - 3)

A = 5y . 2y - 3 . 5y + 5 . 2y - 3 . 5

A = 10y² - 15y + 10y - 15

A = 10y² - 5y - 15

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A 290-kg flatcar 28 m long is moving with a speed of 6.5 m/s along horizontal frictionless rails. A 95-kg worker starts walking
blsea [12.9K]

Answer:

9.33 seconds

60.67 meters

Step-by-step explanation:

A worker with a speed of 3.0 m/s with respect to a car, starts to walk from one end of the car to the other in the direction of motion of the car.

As the car is 28 m long, then the worker will reach the other end of the car in \frac{28}{3} = 9.33 seconds. (Answer)

Now, the car is moving with a speed of 6.5 m/s and in the time of 9.33 seconds, it will move by 6.5 \times 9.33 = 60.67 meters. (Answer)

6 0
3 years ago
What percent of 260 is 247
Sloan [31]
247/260*100%= 95%

95% of 260 is 247~
3 0
3 years ago
Please help giving brain liest if correct
MissTica

Answer:

196 gal/minute

Step-by-step explanation:

divide the time by the amount of gallons

8 0
3 years ago
Read 2 more answers
Mario walked at 3.9 miles per hour for 0.72 hours how far did she walk
nasty-shy [4]
The speed at which Mario can walk is given in the question and it is 3.9 miles/hour. Also we get to know from the question that Mario walked for 0.72 hours. The question requires the answer to the distance for which Mario walked.
Now
Mario in 1 hour can cover a distance of 3.9 miles
The n
The distance covered by Mario in 0.72 hours = (3.9 * 0.72) miles
                                                                         = 2.808 miles
Then the distance covered by mario in o.72 hours is 2.808 miles.
7 0
3 years ago
a metalworker has meal alloy that is 15% copper and another alloy that is 60% copper. how many kilograms of each alloy should th
iragen [17]
Let L be the low copper alloy and H be the high copper alloy.
We need 0.15L + 0.60H = 0.42 and L + H = 100

L=100 - H
Substituting this into the second equation for L, we get:
0.15(100-H) + 0.60H = 0.42(H+L)
15 - 0.15H + 0.60H = 0.42(H+100-H)
15 + 0.45H = 0.42(100)
0.45H = 42 - 15 = 27
H = 27/.45 = 60 lbs

Back substitution, L = 40 lbs.
4 0
3 years ago
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