Answer:
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Begin with the right hand side:
R.H.S = cot θ = 
L.H.S = sin θ cos θ
so, sin θ cos θ ≠
So, the equation is not a trigonometric identity.
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<u>Anther solution:</u>
To prove that ( sin θ cos θ = cot θ ) is not a trigonometric identity.
Assume θ with a value and substitute with it.
Let θ = 45°
So, L.H.S = sin θ cos θ = sin 45° cos 45° = (1/√2) * (1/√2) = 1/2
R.H.S = cot θ = cot 45 = 1
So, L.H.S ≠ R.H.S
So, sin θ cos θ = cot θ is not a trigonometric identity.
By using the triangular inequality, we will see that no triangles can be made with these side lengths.
<h3>
How many triangles can be made with these side lengths?</h3>
Remember that for any triangle with side lengths A, B, and C, the triangular inequality must be true.
This means that the sum of any two sides must be larger than the other side.
A + B > C
A + C > B
B + C > A.
For the given side lengths, we will have:
8 in + 12 in > 24 in
8in + 24 in > 12 in
12 in + 24 in > 8 in.
Now, notice that the first inequality is false. So the triangular inequality is not meet. Then we can't make a triangle with these side lengths.
So we can make 0 unique triangles with these side lengths.
If you want to learn more about triangles:
brainly.com/question/2217700
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Answer:
1/7
Step-by-step explanation:
x/y
Plug in the values.
(2)/(14)
Simplify.
1/7
Try 147? it may be wrong but i though that with that type of thing the middle one is supposed to equal double the bottom.
