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vovangra [49]
3 years ago
8

Can you please help me on -5(-4r-6)=5(6-r)

Mathematics
1 answer:
Wewaii [24]3 years ago
4 0

The answer you are looking for is no solution.

To find this, you first distribute the -5 into the parenthesis (-4r - 6). -5 x -4r = 20r and -5 x -6 = 30.Next, distribute the 5 into the parenthesis (6 - r). 5 x 6 = 30 and 5 x r = 5r.

The equation says 20r + 30 = 5r + 30. Now you solve for r.Subtract 5r from both sides. This leaves the equation to say 15r + 30 = 30. Then subtract 30 from both sides, to get 15r = 0.

At this point, since there is a zero on the opposite side of the variable, you can assume it will be no solution, since multiplying or dividing 0 by anything, is 0. However, I'll finish the problem, to show that it is no solution.

Divide 15 from both sides, leaving r = 0, which is no solution.

I hope this helps!

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How many terms are in the binomial expansion of (3x 5)9? 8 9 10 11
swat32

Answer:

10

Step-by-step explanation:

5 0
2 years ago
Find the coordinates of the image of the point (3, 4) after it has been rotated by <br> 180 degrees
sammy [17]

Answer:

(-3,-4)

Step-by-step explanation:

Flip the coordinate across the graph since it is 180 degrees. (x,y) becomes

(-x,-y)

6 0
3 years ago
In the trapezoid ABCD ( AB ∥ CD ) point M∈ AD , so that AM:MD=3:5. Line l ∥ AB and going trough point M intersects diagonal AC a
geniusboy [140]

Answer:

BC:BN=8:3

Step-by-step explanation:

ABCD is a trapezoid and there is a point m which belongs to AD such that AM:MD=3:5.Line "l" parallel to AB intersects the diagonal AC at p and BD at N.

Now, we know that the parallel lines divide the transversal into the segments with equal ratio, therefore, BN:NC=AM:MD

But, BC= BN+NC

Therefore, BC:BN=(BN+NC):BN

⇒BC:BN=(3+5):3

⇒BC:BN=8:3


4 0
3 years ago
Suppose you'd like to save enough money to pay cash for your next car. The goal is to save an extra $28,000 over the next 6 year
Anna35 [415]

Given:

• Amount to save, A = $28,000

,

• Time, t = 6 years

,

• Interest rate, r = 5.3% ==> 0.053

,

• Number of times compounded = quarterly = 4 times

Let's find the amount that must be deposited into the account quarterly.

Apply the formula:

FV=P(\frac{(1+\frac{r}{n})^{nt}-1}{\frac{r}{n}})

Where:

FV is the future value = $28,000

r = 0.053

n = 4

t = 6 years

Thus, we have:

28000=P(\frac{(1+\frac{0.053}{4})^{4\times6}-1)}{\frac{0.053}{4}}

Let's solve for P.

We have:

\begin{gathered} 28000=P(\frac{(1+0.01325)^{24}-1}{0.01325}) \\  \\ 28000=P(\frac{(1.01325)^{24}-1)^{}}{0.01325}) \\  \\ 28000=P(\frac{1.371509114-1}{0.01325}) \\  \\ 28000=P(\frac{0.371509114}{0.01325}) \end{gathered}

Solving further:

28000=P(28.0384237)

Divide both sides by 28.0384237:

\begin{gathered} \frac{28000}{28.0384237}=\frac{P(28.0384237)}{28.0384237} \\  \\ 998.6=P \\  \\ P=998.6 \end{gathered}

Therefore, the amount that must be deposited quarterly into the account is $998.60

ANSWER:

$998.60

8 0
1 year ago
Write the equation for the quadratic function in standard form
Ede4ka [16]

Answer:

y=x^2+6x+7

Step-by-step explanation:

To write the quadratic in standard form, begin by writing it in vertex form

y = a(x-h)^2+k

Where (h,k) is the vertex of the parabola.

Here the vertex is (-3,-2). Substitute and write:

y=a(x--3)^2+-2\\y=a(x+3)^2-2

To find a, substitute one point (x,y) from the parabola into the equation and solve for a. Plug in (0,7) a y-intercept of the parabola.

7=a((0)+3)^2-2\\7=a(3)^2-2\\7=9a-2\\9=9a\\1=a

The vertex form of the equation is y=(x+3)^2-2.

To write in standard form, convert vertex form through the distributive property.

y=(x+3)^2-2\\y=(x^2+6x+9)-2\\y=x^2+6x+7

8 0
3 years ago
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