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4 years ago

A. x = –4

1 answer:

3 0

Please, please, post only ONE question at a time. The way Brainly is set up, it's very difficult to conclude one problem and then move on to the next in the same session.

Solve y = log3243. I must make the assumption here that you mean:

Solve y = (log to the base 3) of 243.

Solve y = (log 243 in better, more compact form.
3

If you recognize that 243 is an integer power of 3, the problem becomes much easier.
2 3 4 5
Note that 3 = 9, 3 = 27, 3 =81, and 3 = 243.

Also note that the log function and the exponential function are inverses of one another, and that inverse functions "undo" each other.
x
Thus, log 3 is simply x.
3
5
Thus, log 243 = log 3 = 5 (answer).
3 3

Please repost the rest of your questions, one at a time, and then I will gladly help you with them.

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If a square piece of land is 20m long, how much cord is needed to go around it 5 times

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You will need 400 meters of cord.

Step-by-step explanation:

Since it's a square, we know the perimeter of the piece of land is 20 times 4, or 80. Because it is going around it 5 times, we just multiply 80 by 5 to get 400. You will need 400 meters of cord.

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Consider a drug testing company that provides a test for marijuana usage. Among 317 tested subjects, results from 25 subjects w

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Answer:

We conclude that we fail to reject $H_0$ as there is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong.

Step-by-step explanation:

We are given that among 317 tested subjects, results from 25 subjects were wrong.

We have to test the claim that less than 10 percent of the test results are wrong.

Let p = proportion of subjects that were wrong.

So, Null Hypothesis, $H_0$ : p = 10% {means that 10 percent of the test results are wrong}

Alternate Hypothesis, $H_A$ : p < 10% {means that less than 10 percent of the test results are wrong}

The test statistics that would be used here One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{\hat p (1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of test results that were wrong = $\frac{25}{317}$ = 0.08

n = sample of tested subjects = 317

So, test statistics = $\frac{0.08-0.10}{\sqrt{\frac{0.08 (1-0.08)}{317} } }$

= -1.31

The value of z test statistics is -1.31.

Now, the P-value of the test statistics is given by the following formula;

P-value = P(Z < -1.31) = 1 - P(Z $\leq$ 1.31)

= 1 - 0.9049 = 0.095

Now, at 0.05 significance level the z table gives critical value of -1.645 for left-tailed test. Since our test statistics is more than the critical value of z as -1.31 > -1.645, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that we fail to reject $H_0$ as there is not sufficient evidence to warrant support of the claim that less than 10 percent of the test results are wrong.

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3 years ago

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