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Jet001 [13]
3 years ago
10

Complete the equation of the line through (3, -8) and (6,-4). Use exact numbers.

Mathematics
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

y = 4/3x - 12

Step-by-step explanation:

To find the slope of the line, we do (y2 - y1) / (x2 - x1)

If we put in the values, we'll get

(-4 - -8) / (6 - 3)

Simplify and get

(-4 + 8) / 3

4 / 3

Your slope is now 4/3, so you can put it into your equation y = mx + b

y = 4/3x + b

To find b, we can plug in the values from one of your points. Lets use (3, -8)

-8 = 4/3 * 3 + b

Now solve the equation

-8 = 4 + b

-12 = b

Now that you have b, your equation is complete:

y = 4/3x - 12

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Read 2 more answers
Given f(x) = (lnx)^3 find the line tangent to f at x = 3
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Explanation

We must the tangent line at x = 3 of the function:

f(x)=(\ln x)^3.

The tangent line is given by:

y=m*(x-h)+k.

Where:

• m is the slope of the tangent line of f(x) at x = h,

,

• k = f(h) is the value of the function at x = h.

In this case, we have h = 3.

1) First, we compute the derivative of f(x):

f^{\prime}(x)=\frac{d}{dx}((\ln x)^3)=3*(\ln x)^2*\frac{d}{dx}(\ln x)=3*(\ln x)^2*\frac{1}{x}=\frac{3(\ln x)^2}{x}.

2) By evaluating the result of f'(x) at x = h = 3, we get:

m=f^{\prime}(3)=\frac{3}{3}*(\ln3)^2=(\ln3)^2.

3) The value of k is:

k=f(3)=(\ln3)^3

4) Replacing the values of m, h and k in the general equation of the tangent line, we get:

y=(\ln3)^2*(x-3)+(\ln3)^3.

Plotting the function f(x) and the tangent line we verify that our result is correct:

Answer

The equation of the tangent line to f(x) and x = 3 is:

y=(\ln3)^2*(x-3)+(\ln3)^3

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