X+5 = x^2 - x + 2
0 = x^2 -2x - 3
0 = (x-3)(x+1)
x = -1,3
y = -1 + 5 OR y = 3+5
y = 4 OR y = 8
y = 4,8
So we have two ordered pairs, (-1,4) and (3,8).
Hope that helped!
can you mark my answer as brainliest btw?
Answer:
Step-by-step explanation:
you have to use trigonometric functions
cos 30 = adj. /hyp.
cos 30 = 12 / y
y = 12/cos 30 ≅13.86
tan 30 = opp./adj
tan30 = x / 12
x = 12 tan30 ≅6.93
Answer:
3 and 4
Step-by-step explanation:
Answer:
Step-by-step explanation:
There are a total of 10 persons (6 teachers + 4 students) from which a committee of 5 is to be formed. This can be done in 10C5 ways.
The number of ways that a committee can be formed with no students in it is to select 5 teachers out of the pool of 6 teachers available. This can be done in 6C5 ways.
Therefore the total number of ways that the committee can be formed with at least one student in it is 10C5 - 6C5.
10C5 = 252
6C5 = 6
Therefore the required number of ways = 246
