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deff fn [24]
3 years ago
10

Why are tsunamis usually harmless in open water away from the shoreline?

SAT
1 answer:
iragen [17]3 years ago
6 0
This is because I’d deep ocean,tsunami waves may appear only a foot or so high.But as they approach the shoreline and enter shallower water they slow down and begin to grow in energy and height.Since the tops of the waves move faster than the bottoms so it causes them to rise faster.So...if a tsunami is in deep waters it does not really hit the shore and splash around to hurt anyone or anything or any people.It is fine because it’s in the middle of the ocean and not on the shoreline.I hoped I helped even a little bit :3
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The average age of a breed of dog is 19.5 years. if the distribution of their ages is normal and 20% of dogs are older than 22.6
viva [34]

The  standard deviation of the average age of a breed of dog  is said to be 3.69.

<h3>What is the standard deviation about?</h3>

Note that we take:

  • x = dog age has mean 19.5
  • Unknown standard deviation.

Hence:

z = (x - mean) /SD is distributed N (0,1) - mean o standard deviation 1 (standard normal)

Since 20% of dogs are known to be older than 22.6 years:

So 22.6 years is said to be 80th percentile,

Since z matching to 80th percentile (using the standard normal table) s is <em>0.84.</em>

Then one need to plug z, x which is  = 22.6

mean = 19.5 into the stated z equation:

Hence,

0.84 = (22.6 - 19.5)/SD

SD = (22.6 - 19.5)/0.84

= 3.69

Learn more about standard deviation from

brainly.com/question/475676

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