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DiKsa [7]
3 years ago
13

Can someone help me with this equation

Mathematics
1 answer:
vladimir1956 [14]3 years ago
7 0
Question mark =1













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Sloan [31]
AL=5ah!!!!!!!!!! Hope it helps
3 0
3 years ago
What is the value of 9 - [42 - (3 + 2)].
Vlada [557]

9 - [42 - (3 + 2)]

Parentheses first:

9-[42-5]

Brackets next:

9- 37

Now subtract to get -28

8 0
3 years ago
Please help not sure what these are
Leviafan [203]

Answer:

I believe it's the first one

7 0
3 years ago
Given z1 = 1+i and z2 = 2+3i.
Margaret [11]

Answer:

(a) w=2+5i-6=-4+5i

Multiplicative inverse of w will be \frac{1}{-4+5i}

(B) As w is same as the product of z_1\ and\ z_2

So there multiplicative inverse will also be same

Step-by-step explanation:

We have given two complex numbers

z_1=1+i and z_2=3+2i

(a) First we have to find w=z_1z_2

So w=(1+i)(2+3i)=2+3i+2i+6i^2=2+5i+6i^2

As we know that i^2=-1

So w=2+5i-6=-4+5i

Multiplicative inverse :

It is that number when multiply with the number which we have have to find the multiplicative inverse gives result as 1

So multiplicative inverse of w will be \frac{1}{-4+5i}

Because when we multiply -4+5i with \frac{1}{-4+5i} it gives result as 1

(b) As w is same as the product of z_1\ and\ z_2

So there multiplicative inverse will also be same

4 0
3 years ago
a family has five children. the probability of having a girl is 1/2. whats probability of having at leasr 4 girls g'
Dima020 [189]

Answer:

Probability of having at least 4 Girls

= 0.6875

Step-by-step explanation:

Probability of having at least 4 Girls is 1-probability of having exactly 3 girls

Total number of children= 5 = N

Probability of having a girl p = 0.5

Probability of not having a girl q= 0.5

X= 3

Probability of at least 4 girls is given by

Probability= NCX(p)^x(q)^(N-x)

Probability = 5C3(0.5)^3(0.5)^(5-3)

Probability = 5C3(0.5)^3(0.5)^2

Probability= 5!/3!2!(0.5)^3(0.5)^2

Probability= 10(0.125)(0.25)

Probability= 0.3125

Probability of having at least 4 Girls

= 1- 0.3125

= 0.6875

7 0
3 years ago
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