Answer:
18.7 inches
Step-by-step explanation:
The question says that the height of a square pyramid is one half the length of each side. the volume of the pyramid is 972in³ and we are now asked to find the height of the pyramid
----The volume of a square pyramid is
V = A(h/3)
And since the height is one half(3/2) of the base
Let's assume that the base is y inch
Height = 3/2 × y,
Base area = y × y = y²
Volume of the pyramid = 3/2 × y × y² ÷ 3 = 972
Y/2 × y² = 972
Y³ = 1944
Y = ³√1944
Y = 12.48
Since the lenghy of the base is 12.48 in
And the height us 3/2 of y,
H = 3/2 × 12.48
Height is 18.7 inches
9514 1404 393
Answer:
Step-by-step explanation:
The Pythagorean theorem (see Hint) tells you the length of the hypotenuse (c) is ...
c² = 1² + 1² = 2
c = √2 ≈ 1.4142136 . . . units
The estimated value of the length of the hypotenuse is 1.41 units.
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Of course the shaded square will have an area that is the square of that value:
area = s² ≈ 1.41² ≈ 1.99 . . . . . rounded to hundredths
The estimated area of the square is 1.99 square units.
__
<em>Additional comment</em>
Of course, we don't have to estimate. We can use the exact value of the side length to determine the shaded square has an area of ...
area = s² = (√2)² = 2 . . . . exactly
We can also get there by recognizing that the lengths of 1 represent half the length of each of the diagonals of the square. That is, the square's diagonals are both of length 2. The area is half their product, so is (1/2)(2·2) = 2 square units.
Answer:
m = -1
Step-by-step explanation:
18 - 4m = 6 - 16m
18 - 6 = 4m - 16m
12 = -12m
m = 12 / -12
m = -1
X=20
i’m pretty sure that’s the answer
