Yo sup??
we can solve this question by applying trigonometric ratios
cos59=CB/CD
CD=CB/cos59
=7.76
=7.8
Hope this helps.
Answer:
And if we solve for a we got
And the limits for this case are: (214.4; 295.4)
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the annual precipitation of a population, and for this case we know the distribution for X is given by:
Where
and
The confidence level is 95.44 and the signficance is
and the value of
. And the critical value for this case is 
Using this condition we can find the limits
And if we solve for a we got
And the limits for this case are: (214.4; 295.4)
Answer:
2(x+10)
Step-by-step explanation:
Well since sum is addition and the number and 10 are the sum, let’s make the “number“ (x) and add em up. 10+x.
Now we gotta double that sum which is basically
2(10+x)
Answer:
The height above sea level at <em>B</em> is approximately 1,604.25 m
Step-by-step explanation:
The given length of the mountain railway, AB = 864 m
The angle at which the railway rises to the horizontal, θ = 120°
The elevation of the train above sea level at <em>A</em>, h₁ = 856 m
The height above sea level of the train when it reaches <em>B</em>, h₂, is found as follows;
Change in height across the railway, Δh = AB × sin(θ)
∴ Δh = 864 m × sin(120°) ≈ 748.25 m
Δh = h₂ - h₁
h₂ = Δh + h₁
∴ h₂ ≈ 856 m + 748.25 m = 1,604.25 m
The height above sea level of the train when it reaches <em>B</em> ≈ 1,604.25 m