The digit 5 in 4521 has a value that can be found by setting the other digits to zero. It is 500.
The digit 5 in 2615 has a value that can be found by setting the other digits to zero. It is 5.
500 is 100×5.
The digit 5 in 4521 has a value that is <em>100 times</em> the value of the digit 5 in 2615.
You first want to make an equation for the problem. Let x be the number of teams needed since the problem doesn’t include it.
30=5x
Divide 5 by both sides to get x on its own side
*What you do to one side you do to the other
30/5=5x/5
6=x
Answer:
12
Step-by-step explanation:
4,8,12
6,12
They both have 12 in common
Answer:
A is the answer
Step-by-step explanation:
first take out the common factors ithe numerator and then after that take the common factors of denominator and then common terms cancels off and 3/n will remain
