4 years ago

Help please with this question?

1 answer:

7 0

$G(x+1)= \sqrt{(x+1)^2+4} \\ G(x+1)= \sqrt{x^2+2x+1+4} \\ G(x+1)= \sqrt{x^2+2x+5}$

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N76 [4]

1. Use Difference of squares: a^2-b^2=(a+b)(a-b)
(x+k)(x-k)=0

2. Solve for x and k
x=+-k
k=+-x

8 0

4 years ago

djyliett [7]

Answer:

The radius is 1

Step-by-step explanation:

7 0

3 years ago

kolezko [41]

The answer was rounded which is 10.

5 0

4 years ago

Cloud [144]

Answer:

C(t) = 20t

Step-by-step explanation:

The graph of C(t) appears to be linear

The y intercept is 0

The slope is 200/10 = 20

y = mx+b where m is the slope and b is the y intercept

y = 20x+0

y = 20x

C(t) = 20t

4 0

3 years ago

rosijanka [135]

Answer:

I don’t know which answer choice it is since C and D are the same but the answer is supposed to be x < -15.

Step-by-step explanation:

the image has the work shown

5 0

2 years ago