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3 years ago

11

Solve for x

= 0" alt=" \sqrt{x - 2} = 0" align="absmiddle" class="latex-formula">

1 answer:

Firdavs [7]3 years ago

3 0

To solve for x, you need to isolate/get x by itself in the equation:

$\sqrt{x-2} =0$ Square ² both sides to get rid of the square root √

$(\sqrt{x-2} )^2=(0)^2$

x - 2 = 0 Add 2 on both sides

x - 2 + 2 = 0 + 2

x = 2

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nathan smiled at 50 people one day and recorded that 36 people smiled back at him.Based on his observations how many people shou

Olegator [25]

Given :

Nathan smiled at 50 people one day and recorded that 36 people smiled back at him.

To Find :

How many people should Nathan expect to return a smile if he smiles at 650 people over a period of time.

Solution :

Ratio of people smiled by total number of people is :

$R = \dfrac{36}{50}$

Now, it is given that we have to use the given conditions.

Therefore, ratio will be same :

$\dfrac{s}{650}=\dfrac{36}{50}\\\\s = \dfrac{36}{50}\times 650\\\\s = 468$

Therefore, number of smiles Nathan expect to return is 468.

4 0

3 years ago

Which of the following is less than -3?

Lady bird [3.3K]

Any number less than -3, so -3.5, -4, -5, -6, -6.35368, -7, etc.

3 0

3 years ago

anzhelika [568]

Step-by-step explanation:

they need to add up to -56

and multiply to 180

4 0

3 years ago

Write an explicit formula for a_n, the nth term of the sequence 4, -20, 100, ...

saw5 [17]

Answer:

$a_{n}$ = 4 $(-5)^{n-1}$

Step-by-step explanation:

There is a common ratio r between consecutive terms , that is

r = - 20 ÷ 4 = 100 ÷ - 20 = - 5

This indicates the sequence is geometric with nth term ( explicit formula )

$a_{n}$ = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio

Here a₁ = 4 and r = - 5 , then

$a_{n}$ = 4 $(-5)^{n-1}$

3 0

3 years ago

Will give any wanted points!! help quick!!

gayaneshka [121]

Here , the ratio <em><u>UV:</u></em><em><u>VW</u></em> and <em><u>UT:TS</u></em> will be in proportion , so ;

${:\implies \quad \sf \dfrac{UV}{VW}=\dfrac{UT}{TS}}$

Putting the given values ;

${:\implies \quad \sf \dfrac{18}{36}=\dfrac{UT}{24}}$

${:\implies \quad \sf UT=\dfrac{1}{2}\times 24}$

${:\implies \quad \bf \therefore \quad \underline{\underline{UT=12 \:\: units}}}$

4 0

3 years ago