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3 years ago

11

Solve for x

= 0" alt=" \sqrt{x - 2} = 0" align="absmiddle" class="latex-formula">

1 answer:

Firdavs [7]3 years ago

3 0

To solve for x, you need to isolate/get x by itself in the equation:

$\sqrt{x-2} =0$ Square ² both sides to get rid of the square root √

$(\sqrt{x-2} )^2=(0)^2$

x - 2 = 0 Add 2 on both sides

x - 2 + 2 = 0 + 2

x = 2

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What is the solution of 3+ x-2/x-3 less than or equal to 0

bagirrra123 [75]

Answer:

The solution set consists of all the real numbers smaller than or equal to 11/4:

$x\leq \frac{11}{4}$

Step-by-step explanation:

We need to solve for x (that means isolate x on one side of the inequality symbol) in the following inequality:

$3+\frac{x-2}{x-3} \leq 0\\\frac{x-2}{x-3} \leq -3\\x-2\leq -3\,(x-3)\\x-2\leq -3x+9\\x+3x\leq 9+2\\4x\leq 11\\x\leq \frac{11}{4}$

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3 years ago

An IQ test is designed so that the mean is 100 and the standard deviation is 12 for the population of normal adults. Find the sa

Julli [10]

Answer:

Step-by-step explanation:

Given that IQ mean is 100 and std dev = 12 for normal adults

$Confidence level =90%\\Z critical value = 1.645\\Margin of error = 2\\Margin of error = 1.645* std error =2\\Std error = 1.216$

Std error = $\frac{12}{\sqrt{n} } =1.216$

$n=(\frac{12}{1.216} )^2 =97.38$

i.e. sample size should be atleast 97

The required sample size is 97.

This is reasonable as this is greater than 30

Yes. This number of IQ test scores is a fairly large number.

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3 years ago

DUE TODAY BEING HOEST PLs HELLP :(

Triss [41]

The answer is 3:9 or 1:3

3 0

3 years ago

Read 2 more answers

The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti

DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

$P(t)=10000(0.2)^t$

1) $P(0)$ is the population initially.

$P(1)$ is the population after a year.

$\frac{P(1)}{P(0)}$ represents the population increase factor.

So let's evaluate that fraction:

$\frac{P(1)}{P(0)}$

$\frac{10000(0.2)^1}{10000(0.2)^0}$

$\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2$

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

$P(t)=10000(0.2)^{t}$

We want t to represent months.

A full year is 12 months, in a full year we have that $P(1)=10000(0.2)^1=10000(0.2)=2000$

So we want a new P such that $P(12)=2000$ since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) $P(12)=10000(0.87449)^{12}=2000 \text{approximately}$

b) $P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}$

c) $P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}$

d) $P(12)=10000(0.87449)^{12+12}=400 \text{approximately}$

So a is the function we want.

Also another way to look at this:

$P(t)=10000(.2)^t$ where $t$ is in years.

$P(t)=10000(.2^\frac{1}{12})^t$ where $t$ is in months.

And $.2^\frac{1}{12}=0.874485 \text{approximately}$

8 0

4 years ago

A delivery truck weighs 5.5 tons before it is loaded with packages. Once the delivery truck is full of x packages it weighs 6.1

KIM [24]

Answer:

80 packages

Step-by-step explanation:

0.0075*80= 0.6 5.5 + 0.6= 6.1

4 0

2 years ago