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3 years ago

15

Ella drew 40 different pictures for an art show. Twenty of them include a dog in the picture. If she shuffles the pictures and p

icks one at random to give to her friend, what is the probability that she will pick one that includes a dog?
A.
0.2
B.
0.05
C.
0.1
D.
0.5

1 answer:

k0ka [10]3 years ago

6 0

Answer:

0.05

Step-by-step explanation:

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calculate the rate of change <br> -24 ,60) ,( -34, 50<br> please help

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Step-by-step explanation:

the rate of change is the slope of the line connecting both points.

the slope is the ratio y/x indicating how many units y changes, when x changes a certain amount of units when going from one point to another.

so, here

x changes by -10 units (from -24 to -34)

y changes by -10 units (from 60 to 50).

the slope or rate of change is -10/-10 = 1/1 = 1

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2 years ago

A sphere has a radius of 17 inches. Find the volume of the sphere described. Use 3.14 for . Round your answer to the nearest hun

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Answer:

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Step-by-step explanation:

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3 years ago

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Arlecino [84]

Answer:

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Step-by-step explanation:

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2 years ago

PLEASE PLEASE ANSWER!

muminat

The area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = $\frac{1}{2}\times \pi r^2$

$$=\frac{1}{2}\times \pi\times 4^2$

$$=\frac{1}{2}\times \pi\times 16$

Area of the semi-circle = $$8\pi$ cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

$AC^2+BC^2=AB^2$

$AC^2+4^2=8^2$

$AC^2=64-16$

$AC^2=48$

$AC=4\sqrt{3}$ cm

Base of the triangle ABC = $4\sqrt{3}$ cm

Height of the triangle = 4 cm

Area of the triangle ABC = $\frac{1}{2}\times b \times h$

$$=\frac{1}{2}\times 4\sqrt{3} \times 4$

Area of the triangle ABC = $8\sqrt{3}$ cm²

Area of the shaded region

= Area of the semi-circle – Area of the triangle ABC

= $$8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2$

= $$8(\pi \ -\sqrt{3})\ \text{cm}^2$

Hence the area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

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3 years ago

Here's a graph of a linear function. Write the

Softa [21]

Answer:

y = 3/2x - 3

Step-by-step explanation:

Slope = 3/2

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y = mx + b

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