Answer:
Valine-Leucine-Proline-Lysine-Histidine
Explanation:
The central dogma of biology is the process by which DNA is used to synthesize RNA and subsequently amino acid sequence (PROTEIN). The processes of transcription and translation is used in gene expression. Transcription is the process whereby the information encoded in a DNA molecule is used to synthesize a mRNA molecule. Transcription is catalyzed by RNA polymerase enzyme, which uses complementary base pairing rule i.e Adenine(A)-Thymine(T), Guanine(G)-Cytosine(C) pairing.
N.B: Thymine is replaced by Uracil in the mRNA
For the above DNA sequence: CAC GAC GGA TTC GTA, the mRNA sequence will be: GUG CUG CCU AAG CAU
Translation is the second process of gene expression which involves the synthesis of an amino acid sequence from an mRNA molecule. The mRNA is read in a group of three nucleotides called CODON. Each codon specifies an amino acid (see attached image for genetic code)
Based on the attached genetic code, an mRNA sequence: GUG CUG CCU AAG CAU will encode an amino acid sequence: Valine(Val) - Leucine (Leu) -Proline (Pro) -Lysine (Lys) - Histidine (His).
GUG specifies Valine amino acid
CUG specifies Leucine amino acid
CCU specifies Proline amino acid
AAG specifies Lysine amino acid
CAU specifies Histidine amino acid
Answer:
1) CO₂
2) 0.2551 g
Explanation:
The balanced reactions are:
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
MgCO₃ + 2HCl → MgCl₂ + H₂O + CO₂
1) The gas produced is CO₂.
2) Calculate mass of CaCO₃:
(0.5236 g) (0.4230) = 0.2215 g CaCO₃
Convert to moles:
(0.2215 g CaCO₃) (1 mol / 100.1 g) = 0.002213 mol CaCO₃
Find moles of CaCO₃:
(0.002213 mol CaCO₃) (1 mol CO₂ / mol CaCO₃) = 0.002213 mol CO₂
Convert to mass:
(0.002213 mol CO₂) (44.01 g / mol) = 0.09738 g CO₂
Calculate mass of MgCO₃:
(0.5236 g) (0.5770) = 0.3021 g MgCO₃
Convert to moles:
(0.3021 g MgCO₃) (1 mol / 84.31 g) = 0.003583 mol MgCO₃
Find moles of MgCO₃:
(0.003583 mol MgCO₃) (1 mol CO₂ / mol MgCO₃) = 0.003583 mol CO₂
Convert to mass:
(0.003583 mol CO₂) (44.01 g / mol) = 0.1577 g CO₂
Total mass of CO₂:
0.09738 g CO₂ + 0.1577 g CO₂ = 0.2551 g CO₂
Answer: pro is one cell - archaebacteria, eubacteria
eukaryote is more than one - protista, fungi, plantae, animalia.
Explanation:
Robert Hooke contribute to the cell theory because he was the first person to use the term “cell.”
<h3>What is contribution of Robert Hooke to cell theory?</h3>
Hooke observing cork through his microscope in which he saw tiny cavities which he described as cells. Hooke's discovery led to the foundation of cell theory.
So we can conclude that Robert Hooke contribute to the cell theory because he was the first person to use the term “cell.”
Learn more about cell here: brainly.com/question/13123319
