All categories

3 years ago

In which process CO2, is released as a by-product of oxidation-reduction reactions?

Biology

1 answer:

melamori03 [73]3 years ago

5 0

Answer:

B) Krebs cycle (citric acid cycle)

Explanation:

Glycolysis breaks glucose into two pyruvate molecules. Pyruvate is decarboxylated into acetyl CoA and the reaction occurs in the matrix of mitochondria. In the mitochondrial matrix, acetyl CoA enters Kreb's cycle and is broken down into CO2 and H2O. For one molecule of acetyl CoA, two molecules of CO2 are released as a by-product. Therefore, out of three carbon atoms of pyruvate, two are released as CO2 during Kreb's cycle.

You might be interested in

Describe how an algal bloom might alter the local carbon cycle in that ecosystem.

AlladinOne [14]

Answer:

Explanation:

During an algal bloom the species produce a toxic chemical substance which is harmful to animals that feed on the algae that causes a tint in the water because of the photosynthetic pigments is known as a red tide a red tide may or may not be harmful . Nonetheless algal bloom can produce both beneficial and harmful cycles.

It is beneficial because it can provide organic compounds needed by higher organisms, for this reason productivity increases because there's more algae in the water which means that more carbon dioxide is used from the atmosphere and that more oxygen is being released into the atmosphere which is needed and necessary for many living things

4 0

3 years ago

How does a fungus get energy

nydimaria [60]

All fungi are heterotrophic, which means that they get the energy they need to live from other organisms. Like animals, fungi extract the energy stored in the bonds of organic compounds such as sugar and protein from living or dead organisms.

5 0

4 years ago

What determines how an atom bonds with other atoms?

Hitman42 [59]

The number of each electron in its shell determines how an atom combines with other atoms to form compounds.

6 0

3 years ago

Read 2 more answers

In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant

Ivenika [448]

Answer and Explanation:

Available data:

Comb shape is determined by genes at two loci (R, r and P, p).

The walnut comb genotype is R_P_.

The rose comb genotype is R_pp.

The pea comb genotype is rrP_.

The single genotype is rrpp.

a. Walnut crossed with single produces 1 walnut, 1 rose, 1 pea, and 1 single offspring:

Parental) RrPp x rrpp

Gametes) RP Rp rP rp rp rp rp rp

Punnet Square) RP Rp rP rp

rp RrPp Rrpp rrPp rrpp

rp RrPp Rrpp rrPp rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

b. Rose crossed with pea produces 20 walnut offspring.

Parental) RRpp x rrPP

Gametes) Rp Rp Rp Rp rP rP rP rP

Punnet Square) Rp Rp Rp Rp

rP RrPp RrPp RrPp RrPp

F1 phenotype: 100% walnut.

F1 genotype: 16/16 RrPp.

c. Pea crossed with single produces 1 single offspring.

This is not possible, because the pea genotype involves at least one dominant allele P. There are two possible crosses: rrPp x rrpp, which must produce half of the progeny pea and the other half single, or rrPP x rrpp which produce a whole pea progeny with no single offspring.

Parental) rrPp x rrpp

Gametes) rP rp rP rp rp rp rp rp

Punnet Square) rP rp rP rp

rp rrPp rrpp rrPp rrpp

rp rrPp rrpp rrPp rrpp

F1 phenotype: 50% pea, and 50% single.

F1 genotype: 8/16 rrPp, 8/16 rrpp.

d. Rose crossed with pea produces 2 walnut, 1 single, and 1 pea offspring.

This is not possible, because having one of the parents with a rose phenotype involves at least one R allele, which means that there must be rose phenotype in the progeny.

Parental) Rrpp x rrPp

Gametes) Rp Rp rp rp rP rP rp rp

Punnet Square) Rp Rp rp rp

rP RrPp RrPp rrPp rrPp

rP RrPp RrPp rrPp rrPp

rp Rrpp Rrpp rrpp rrpp

rp Rrpp Rrpp rrpp rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

e. Rose crossed with single produces 31 rose offspring.

Parental) RRpp x rrpp

Gametes) Rp Rp Rp Rp rp rp rp rp

Punnet Square) Rp Rp Rp Rp

rp Rrpp Rrpp Rrpp Rrpp

F1 phenotype: 100% rose (31 individuals equal 100% of the progeny).

F1 genotype: 16/16 Rrpp.

f. Rose crossed with single produces 10 rose and 11 single offspring.

Parental) Rrpp x rrpp

Gametes) Rp Rp rp rp rP rP rp rp

Punnet Square) Rp Rp rp rp

rp Rrpp Rrpp rrpp rrpp

F1 phenotype: 50% rose, 50% single.

F1 genotype: 8/16 Rrpp, 8/16 rrpp.

3 0

3 years ago

Bones are connected to each other by:

romanna [79]

They are connected by tendons

4 0

3 years ago

Read 2 more answers