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Vanyuwa [196]
3 years ago
7

Wha is the square root of two

Mathematics
2 answers:
earnstyle [38]3 years ago
5 0
The answer is four.............
PolarNik [594]3 years ago
4 0
1/2 to the power of 2
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Jake has just become the senior marketing rep for a new chain of upscale hotels. His first responsibility is to develop a
cluponka [151]

Answer:

Startup.

Step-by-step explanation:

If Jake has just become the senior marketing rep for a new chain of upscale hotels, his first responsibility is to develop a  plan, commonly referred to as the  startup.

5 0
3 years ago
Can someone answer this please
Alexxandr [17]

Answer:

Range: (-∞, 0]

General Formulas and Concepts:

<u>Algebra I</u>

  • Range is the set of y-values that are outputted by function f(x)

Step-by-step explanation:

When we graph the equation, we should see that our y-values span from -∞ to 0. Since 0 is a closed dot, it is inclusive in the range:

(-∞, 0] or y ≤ 0

4 0
3 years ago
Which expression is equivalent to 4√6/3
Nookie1986 [14]

Answer:

\frac{4}{3}{\sqrt3}

Step-by-step explanation:

The question seem incomplete;

The full question is

<em>Which expression is equivalent to 4√6/3√2 </em>

<em></em>

Given

4√6/3√2

Required

Find equivalent

4\sqrt6/3\sqrt2

Rewrite Expression

\frac{4\sqrt6}{3\sqrt2}

Expand the above expression

\frac{4\ *\ \sqrt6}{3\ * \ \sqrt2}

Further split the fraction

\frac{4}{3}\ *\ \frac{\sqrt6}{\sqrt2}

Using rule of surds;

\frac{\sqrt a}{\sqrt b} = \sqrt{\frac{a}{b}}

So, the above expression becomes

\frac{4}{3}\ *\ \sqrt{\frac{6}{2}}

\frac{4}{3}\ *\ {\sqrt3}

\frac{4}{3}{\sqrt3}

At this stage, the expression cannot be further simplified;

Hence, 4√6/3√2  = \frac{4}{3}{\sqrt3}

4 0
3 years ago
2log(x+11) = (1/2)^x
Lina20 [59]
X = -1

Hope this helps!
7 0
3 years ago
Read 2 more answers
DONT ANSWER IF YOU DONT KNOW THE ANSWER
maks197457 [2]

Answer:

A

Step-by-step explanation:

A is the answer for the first question I did the math on edge

The second one after is B

We are Simplifying Rational Expressions with Negative Exponents

7 0
3 years ago
Read 2 more answers
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