Divide 25/9 and you'll get the decimal 2.7 repeating boom decimal.
<span>15 0/1
In 5 1/4, multiply the whole number 5 by the denominator of the fraction 4 to get 20.<span> This shows that the whole number represents 20/4
</span></span><span>To find the numerator when an improper fraction use addition.
<span><span>20/4 <span>+ </span>1/4 = 21</span><span>/</span><span>4
</span></span></span><span>Flip 7/20 by swapping the numerator and the denominator to 20/7.
</span><span>Multiply the numerators then multiply the denominators. 21/4 X 20/7 = 420/28.
</span><span>Simplify fraction 420/28 by dividing out the greatest common factor which is 28 from the numerator and denominator. 420/28 = 15/1.
</span><span>Divide the numerator 15 by the denominator 1 to get 15 with remainder 0. The remainder is the new numerator 15 0/1 is the answer to the mixed number.</span>
Answer:
50
Step-by-step explanation:
150 divided by 3
![\dfrac{B_x \sqrt{74_x}}{1D_x}+J_x51_x=4G3_x](https://tex.z-dn.net/?f=%5Cdfrac%7BB_x%20%5Csqrt%7B74_x%7D%7D%7B1D_x%7D%2BJ_x51_x%3D4G3_x)
A=10, B=11, C=12, etc.
![\dfrac{11\cdot x^0\cdot \sqrt{7\cdot x^1+4\cdot x^0}}{1\cdot x^1+13\cdot x^0}+19\cdot x^0\cdot (5\cdot x^1+1\cdot x^0)=4\cdot x^2+16\cdot x^1+3\cdot x^0\\\\\dfrac{11\sqrt{7x+4}}{x+13}+19(5x+1)=4x^2+16x+3\\\\\dfrac{11\sqrt{7x+4}}{x+13}+95x+19=4x^2+16x+3\\\\11\sqrt{7x+4}+95x(x+13)+19(x+13)=(4x^2+16x+3)(x+13)\\\\11\sqrt{7x+4}+95x^2+1235x+19x+247=4x^3+52x^2+16x^2+208x+3x+39\\\\11\sqrt{7x+4}=4x^3-27x^2-1043x-208\\\\121(7x+4)=(4x^3-27x^2-1043x-208)^2](https://tex.z-dn.net/?f=%5Cdfrac%7B11%5Ccdot%20x%5E0%5Ccdot%20%5Csqrt%7B7%5Ccdot%20x%5E1%2B4%5Ccdot%20x%5E0%7D%7D%7B1%5Ccdot%20x%5E1%2B13%5Ccdot%20x%5E0%7D%2B19%5Ccdot%20x%5E0%5Ccdot%20%285%5Ccdot%20x%5E1%2B1%5Ccdot%20x%5E0%29%3D4%5Ccdot%20x%5E2%2B16%5Ccdot%20x%5E1%2B3%5Ccdot%20x%5E0%5C%5C%5C%5C%5Cdfrac%7B11%5Csqrt%7B7x%2B4%7D%7D%7Bx%2B13%7D%2B19%285x%2B1%29%3D4x%5E2%2B16x%2B3%5C%5C%5C%5C%5Cdfrac%7B11%5Csqrt%7B7x%2B4%7D%7D%7Bx%2B13%7D%2B95x%2B19%3D4x%5E2%2B16x%2B3%5C%5C%5C%5C11%5Csqrt%7B7x%2B4%7D%2B95x%28x%2B13%29%2B19%28x%2B13%29%3D%284x%5E2%2B16x%2B3%29%28x%2B13%29%5C%5C%5C%5C11%5Csqrt%7B7x%2B4%7D%2B95x%5E2%2B1235x%2B19x%2B247%3D4x%5E3%2B52x%5E2%2B16x%5E2%2B208x%2B3x%2B39%5C%5C%5C%5C11%5Csqrt%7B7x%2B4%7D%3D4x%5E3-27x%5E2-1043x-208%5C%5C%5C%5C121%287x%2B4%29%3D%284x%5E3-27x%5E2-1043x-208%29%5E2)
![121(7x+4)=(4x^3-27x^2-1043x-208)^2\\\\847x+484=16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433888 x + 43264\\\\16 x^6 - 216 x^5 - 7615 x^4 + 54658 x^3 + 1099081 x^2 + 433041 x +42780=0](https://tex.z-dn.net/?f=121%287x%2B4%29%3D%284x%5E3-27x%5E2-1043x-208%29%5E2%5C%5C%5C%5C847x%2B484%3D16%20x%5E6%20-%20216%20x%5E5%20-%207615%20x%5E4%20%2B%2054658%20x%5E3%20%2B%201099081%20x%5E2%20%2B%20433888%20x%20%2B%2043264%5C%5C%5C%5C16%20x%5E6%20-%20216%20x%5E5%20-%207615%20x%5E4%20%2B%2054658%20x%5E3%20%2B%201099081%20x%5E2%20%2B%20433041%20x%20%2B42780%3D0)
Now, the "only" thing that remains to do is solving the above equation.
While making this problem I only made sure it has a solution. I didn't try to solve it myself and I didn't know it will end up with such "convoluted" polynomial. Sorry to everyone who tried to solve it... m(_ _)m
I think the best way to approach it is using the rational root theorem since we know that
. Moreover we can deduce that
since there is
and
.
After you succesfully solve it, you should get the answer
.
Answer:
x^2+6x+5
Step-by-step explanation:
(x+1)(x+5)= x^2+5x+1x+5