Which group of 3 cards would allow Carlos to win with 21 points?

brilliants [131]

Recall that the conversion of 155% to decimal is to divide by 100. Thus, 155%=1.55.

Now, multiply this by 80: $1.55 * 80=124$

So our answer is 124.

8 0

2 years ago

Read 2 more answers

The equation f(x)=x−5 translated 4 units to the left is g(x)=

elixir [45]

The equation of the function g(x) is g(x) = x - 1

<h3>How to determine the equation of the function g(x)?</h3>

The given parameters are:

f(x) = x - 5

The above function f(x) is translated left by 4 units

So, we have

g(x) = f(x + 4)

This gives

f(x + 4) = x + 4- 5

Evaluate the sum

f(x + 4) = x - 1

So, we have:

g(x) = x - 1

Hence, the equation of the function g(x) is g(x) = x - 1

Read more about function transformation at:

brainly.com/question/10904859

#SPJ1

3 0

1 year ago

Olivia has 48 slices of ham and 36 slices of cheese to make sandwiches.

serious [3.7K]

The greatest number of sandwiches that Olivia can make is 12.

3 slices of cheese will be on each sandwich

Solution:

Given that, Olivia has 48 slices of ham and 36 slices of cheese to make sandwiches.

We have to find what is the greatest number of sandwiches that Olivia can make? And how many slices of cheese will be on each sandwich?

Let the number of sandwiches be "n"

Then, number of slices of ham per sandwich $=\frac{48}{n}$

And, number of slices of cheese per sandwich $=\frac{36}{n}$

As slices can’t be fractions, "n" should be a factor of 48 and 36. So now let us find H.C.F of 48 and 36 as we want greatest number of sandwiches that Olivia can make.

The factors of 48 are: 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, and 36

The common factors are those which appear on both factors of 48 and 36 are 1, 2, 4, 6, and 12.

Out of these common factors, 12 is the greatest

So, H.C.F of 48 and 36 is 12, which means n = 12

Then, number of cheese slices per sandwich $=\frac{36}{12}=3$

Hence, 12 sandwiches can be made with 3 slices of cheese per sandwich.

8 0

3 years ago

0.01 × 0.001 answer This

WINSTONCH [101]

Answer:

0.00001

Step-by-step explanation:

6 0

2 years ago

Do political science classes require less writing than history classes? The 55 randomly selected political science classes assig

tia_tia [17]

Answer:

No, political science classes does not require less writing than history classes.

Step-by-step explanation:

We are given that the 55 randomly selected political science classes assigned an average of 19.6 pages of essay writing for the course. The standard deviation for these 55 classes was 4.8 pages.

The 50 randomly selected history classes assigned an average of 20.2 pages of essay writing for the course. The standard deviation for these 50 classes was 3.3 pages.

Let $\mu_1$ = mean writing required by political science classes

$\mu_2$ = mean writing required by history classes

SO, Null Hypothesis, $H_0$ : $\mu_1-\mu_2\geq0$ or $\mu_1\geq \mu_2$ {means that political science classes require more or equal writing than history classes}

Alternate Hypothesis, $H_A$ : $\mu_1-\mu_2$ or $\mu_1$ {means that political science classes require less writing than history classes}

The test statistics that will be used here is Two-sample t test statistics as we don't know about the population standard deviations;

T.S. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n__1+_n__2-2$

where, $\bar X_1$ = sample average writing for political science course= 19.6 pages

$\bar X_2$ = sample average writing for history course= 20.2 pages

$s_1$ = sample standard deviation for political science classes = 4.8 pages

$s_2$ = sample standard deviation for history classes = 3.3 pages

$n_1$ = sample of selected political science classes = 55

$n_2$ = sample of selected history classes = 50

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(55-1)\times 4.8^{2}+(50-1)\times 3.3^{2} }{55+50-2} }$ = 4.154

So, the test statistics = $\frac{(19.6-20.2)-(0)}{4.154 \times \sqrt{\frac{1}{55}+\frac{1}{50} } }$ ~ $t_1_0_3$

= -0.739

Now at 0.01 significance level, the t table gives critical value of -2.367 at 103 degree of freedom for left-tailed test. Since our test statistics is more than the critical value of t as -0.739 > -2.367, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that political science classes require more or equal writing than history classes.

8 0

3 years ago