What is the equation of a circle with center (2,-5) and radius 4?

Mathematics

1 answer:

anastassius [24]3 years ago

7 0

Answer:

Choice C

Step-by-step explanation:

The Equation of a circle is (x-h)^2+(y-k)^2=r^2, where h and k are the x and y coordinates respectively of the center of the circle, and r is the radius. Because the center here is (2, -5), we have (x-2)^2+(y- - 5)^2, and the two minuses become (y+5)^2. This eliminates A and B. The radius is 4, so r^2=16, and thus, we get C.

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The required value after simplification of the s = -16/3. None of these are correct.

Given that,
To simplify $[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2$ and to find the value of s in $x^s$ .

<h3>What is simplification?</h3>

The process in mathematics to operate and interpret the function to make the function simple or more understandable is called simplifying and the process is called simplification.

Simplification,

$=[\frac{x^{2/3}x^{-1/2}}{x\sqrt{x^3}\sqrt[3]{x}}]^2\\= \frac{x^{4/3}x^{-1}}{x^2x^3*{x}^{2/3}}\\= \frac{x^{1/3}}{x^{17/3}}\\=x^{-16/3}$
Comparing with $x^S$
s = -16/3