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4 years ago

8

The sum of two positive numbers is 5 times their difference. What is the ratio of the larger number to the smaller number?

1 answer:

Anna11 [10]4 years ago

4 0

Let the two numbers be x and y

x + y = 5(x-y)
x + y = 5x -5y
6y = 4x
x= (6/4)y
x= (3/2)y

there the ratio is 3/2

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If 2(6 + 3x) + 1 = - 5 + 3(x - 1), what is the value of x?

Stels [109]

Answer: x = -7

Step-by-step explanation:

2(6 + 3x) + 1 = - 5 + 3(x - 1)

(2) (6) + (2) (3x) + 1 = -5 + (3) (x) + (3) (-1)

12 + 6x + 1 = - 5 + 3x + - 1

( 6x ) + ( 12 - 1 ) = ( 3x ) + ( -5 + -3 )

6x + 13 = 3x - 8

6x + 13 - 3x = 3x - 8 - 3x

3x + 13 = -8

3x + 13 - 13 = -8 - 13

3x = -21

3x/3 -21/3

X = -7

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3 years ago

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Lloyd solves the equation 24x + 18(x – 2) = 216 for x. Some of his steps are shown.

Elena-2011 [213]

Answer:

Hi there!

Your answer is:

To get from step 3 to step 4, Lloyd added 36 to both sides. On the left side, this equaled 0 due to the additive inverse property! (-36 + 36 = 0!) On the right side, 36 is added to 216! (216+36 = 252)

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4 years ago

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Complete the steps to demonstrate why you multiply by the reciprocal when dividing fractions

choli [55]

1/2 ÷ 1/2
= 1/2 ÷ 2/1
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4 years ago

The partial fraction decomposition of 9 x 11 6 x 2 23 x 21 can be written in the form of f ( x ) 2 x 3 g ( x ) 3 x 7 , where

svlad2 [7]

Answer:

$f(x) = -1$

$g(x) =6$

$\frac{-1}{2x + 3} + \frac{6}{3x + 7}$

Step-by-step explanation:

The question is unreadable, however the real polynomial is:

The polynomial fraction is:

$P = \frac{9x + 11}{6x^2 + 23x + 21}$

And the decomposition is:

$\frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

The solution is as follows:

$P = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

Substitute the expression for P

$\frac{9x + 11}{6x^2 + 23x + 21} = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

Expand the numerator of the polynomial

$\frac{9x + 11}{(2x + 3)(3x + 7)} = \frac{f(x)}{2x + 3} + \frac{g(x)}{3x + 7}$

Take LCM

$\frac{9x + 11}{(2x + 3)(3x + 7)} = \frac{f(x)*(3x + 7) + g(x)*(2x + 3)}{(2x + 3)(x + 7)}$

Cancel out both denominators

$9x + 11} = f(x)*(3x + 7) + g(x)*(2x + 3)$

Represent f(x) as A and g(x) as B

$9x + 11} = A*(3x + 7) + B*(2x + 3)$

Open bracket

$9x + 11} = 3Ax + 7A + 2Bx + 3B$

$9x + 11} = 3Ax + 2Bx+ 7A + 3B$

$9x + 11} = (3A + 2B)x+ 7A + 3B$

By comparison:

$3A + 2B = 9$ ---- (1)

$7A + 3B =11$ ---- (2)

Make B the subject in (1)

$B = \frac{9 - 3A}{2}$

Substitute $B = \frac{9 - 3A}{2}$ in (2)

$7A + 3(\frac{9 - 3A}{2}) = 11$

Multiply through by 2

$2*7A +2* 3(\frac{9 - 3A}{2}) = 11*2$

$14A + 3(9 - 3A) = 22$

$14A + 27 - 9A = 22$

Collect Like Terms

$14A - 9A = 22-27$

$5A = -5$

$A = \frac{-5}{5}$

$A = -1$

Recall that:

$B = \frac{9 - 3A}{2}$

$B = \frac{9 - 3 * -1}{2}$

$B = \frac{9 + 3}{2}$

$B = \frac{12}{2}$

$B = 6$

A = -1 and B = 6

$3A + 2B = 9$ ---- (1)

$7A + 3B =11$ ---- (2)

So:

$f(x) = A$

$f(x) = -1$

$g(x) =B$

$g(x) =6$

And the decomposition is:

$\frac{-1}{2x + 3} + \frac{6}{3x + 7}$

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3 years ago

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Sladkaya [172]

There would be 40 20cent coins, 40 10cent coins, and 40 5cent coins.

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3 years ago

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