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r-ruslan [8.4K]
2 years ago
11

Help plz i will give brainist

Mathematics
1 answer:
Lemur [1.5K]2 years ago
4 0

Answer:

Hes correct with number 1 aka answer A

Step-by-step explanation:

Its talking abt in the middle hes suppose to divide the six bc at the end it will have 1/8-1/8-1/8 and 2 negatives make a positive meaning it would be 2/8-1/8=1/8 there for number 1 aka A is right btw i want brainiest for explanation thx :)

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Mrs.Maxwell is buying pencils for her students. She has 3 classes of 28 students each. For Valentine’s Day, she wants to give ea
kirill115 [55]

Answer:

the answer might be 336 sorry if i am not right

Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
I have completed the first three parts of this question, but now need help to finish...I need to calculate the ratios of the 4 l
galben [10]

At first, we will find the lengths of LK, Lm, ON, OP, then use them to find the ratios between them

The rule of the distance is

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

For LK

Since L = (3, 6), K = (1,5.33), then

\begin{gathered} LK=\sqrt{(3-1)^2+(6-5.33)^2} \\ LK=\sqrt{4+0.4489} \\ LK=\sqrt{4.4489} \end{gathered}

For LM

Since L = (3, 6), M = (5, 6.67), then

\begin{gathered} LM=\sqrt{(3-5)^2+(6-6.67)^2} \\ LM=\sqrt{4+0.4489} \\ LM=\sqrt{4.4489} \end{gathered}

For ON

Since O = (3, 2.59) and N = (5, 4.2), then

\begin{gathered} ON=\sqrt{(3-5)^2+(2.59-4.2)} \\ ON=\sqrt{4+2.5921} \\ ON=\sqrt{6.5921} \end{gathered}

For OP

Since O = (3, 2.59), P = (1, 0.99), then

\begin{gathered} OP=\sqrt{(3-1)^2+(2.59-0.99)^2} \\ OP=\sqrt{4+2.56} \\ OP=\sqrt{6.56} \end{gathered}

Now let us find the ratios between them

\begin{gathered} \frac{KL}{LM}=\frac{\sqrt{4.4489}}{\sqrt{4.4489}}=1 \\ \frac{PO}{ON}=\frac{\sqrt{6.56}}{\sqrt{6.5921}}=0.9975\approx1 \\ \frac{KL}{LM}=\frac{PO}{ON}=1 \end{gathered}

That means, Parallel lines intercept equal parts

By joining MP

We will have Triangle KPM

Since KL = LM ------- Proved using the distance formula

Since LQ // KP ------ Given

Then MQ = QP ------- Using the theorem down

The theorem

If a line is drawn from a midpoint of one side of a triangle parallel to the opposite side, then it will intersect the 3rd side in its midpoint (Q is the midpoint of MP)

Parallel lines intercept equal parts

7 0
1 year ago
PLEASE HELP!!
madam [21]

The distance traveled by the ray will be 26 inches. Then the correct option is B.

<h3>What is coordinate geometry?</h3>

Coordinate geometry is the study of geometry using the points in space. Using this, it is possible to find the distance between the points, the dividing line is m:n ratio, finding the mid-point of the line, etc.

In a science experiment, a student concluded that a ray has to travel a distance from one corner at the top of the rectangular prism to the opposite side where the surface touching the floor is intersected.

If the length, width, and height of the prism are given as 24 inches and 8 inches, 6 inches respectively.

Then the distance traveled by the ray will be

We know the formula

D² = L² + W² + H²

We have

L = 24 in

W = 6 in

H = 8 in

Then the distance will be

D² = 24² + 6² + 8²

D² = 576 + 36 + 64

D² = 676

D = 26 in

Thus, the correct option is B.

More about the coordinate geometry link is given below.

brainly.com/question/1601567

#SPJ1

7 0
1 year ago
I need some help please
Galina-37 [17]

Answer:

  1. Hexagon
  2. Heptagon

Step-by-step explanation:

The first shape has 6 sides. Hence, it is called a hexagon.

The second shape has 7 sides. Hence, it is called a heptagon.

8 0
1 year ago
Read 2 more answers
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
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