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lozanna [386]
3 years ago
12

Find the sum of all solutions to $(4x+3)(x-8)+(x-1)(4x+3)=0$

Mathematics
1 answer:
Gemiola [76]3 years ago
6 0

Answer:

3 3/4

Step-by-step explanation:

(4x+3)(x-8)+(x-1)(4x+3)=0

Factor out 4x+3

(4x+3)( x-8+x-1) =0

Combine terms

(4x+3) ( 2x-9) =0

Using the zero product property

4x+3 = 0    2x-9 =0

4x=-3         2x = 9

x = -3/4       x = 9/2

Sum the solutions

-3/4 + 9/2

-3/4 + 18/4

15/4

3 3/4

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