I need help with these questions.
1 answer:
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See the picture for all detail, I have done it by hand.
Few important steps;
-Take the first derivative
-Put it equal to zero
-you get the x value which is equal to 11
-Now for the check that x=11 is the least value or not, take the second derivative
-As, the 2nd derivative is positive so it is the least value
As x=0 in 1964 add 11 to it so at x=11 we get 1975 so in this year car have least value
Few important steps;
-Take the first derivative
-Put it equal to zero
-you get the x value which is equal to 11
-Now for the check that x=11 is the least value or not, take the second derivative
-As, the 2nd derivative is positive so it is the least value
As x=0 in 1964 add 11 to it so at x=11 we get 1975 so in this year car have least value
Answer:
$69
Step-by-step explanation:
Given
Required
Determine the cash before purchase
To get the her amount before the purchase, we simply add both given parameters together.
This is done as follows;
Substitute 0 for Amount Left and 60 for Purchase
<em>Hence, she had $69 before the purchase</em>