1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dahasolnce [82]
3 years ago
7

20x\cdot 45x\cdot 123x+3\left\{x+3x\cdot \frac{1}{6}\right\}-129x=1223

Mathematics
1 answer:
Tamiku [17]3 years ago
5 0

Answer:

x=0.224403

Step-by-step explanation:

You might be interested in
Pls help I need dis for a good grade
love history [14]

111) 5:4

112) 3.6

113) -4

114) 0.3 units down, 0.4 units to the left

5 0
3 years ago
Read 2 more answers
2.-3(x-2) OS<br> (1 Point)<br> Enter your answer
Fantom [35]

Answer:

-3x+6

Step-by-step explanation:

Again, you multiply -3 times x and you get -3x, then you multiply -3 times -6 and since you are multiplying two negative numbers the result becomes positive so you get +6. Result = -3x+6

6 0
2 years ago
How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%
blondinia [14]

The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}

So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

But √12 = √(3•4) = 2√3, so

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}

7 0
2 years ago
SIMPLIFY (4-74+7) A. 223 B. 9 27 C. 9+2/7 D. 9
sesenic [268]

Answer:

The correct option is D.

Step-by-step explanation:

The given expression is

(4-\sqrt{7})(4+\sqrt{7})

Difference of two squares property:

a^2-b^2=(a+b)(a-b)

Using the above property, the given expression can be written as

(4)^2-(\sqrt{7})^2

Applying square we get

16-7

9

Therefore the correct option is D.

6 0
3 years ago
HELPPPPPP pleeeeease
dusya [7]

Answer: x = 2 Hope this helps, please consider making me Brainliest.

Step-by-step explanation:

Let's solve for x:

4x + 6 + 2x = 18

4x + 2x = 12

6x = 12

x = 2

Hope this helps, please consider making me Brainliest.

8 0
2 years ago
Read 2 more answers
Other questions:
  • Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations. 2x+y+
    5·1 answer
  • Sophia is 8 years older than Lila. Twenty years ago Sophia was three times as old as Lila. How old is each now?
    10·2 answers
  • (D2+6d+9)+(d3-6d+9)
    15·2 answers
  • F(n) = 4(n-1) + 7<br><br>fine the first three(3) terms in the sequence show all work​
    5·2 answers
  • Answer as soon as possible
    5·1 answer
  • Help me with this pls
    5·2 answers
  • Algebra 1 unit 4 test
    13·2 answers
  • Triangle XYZ has vertices X(1, 6), Y(5, 2), and Z(0, 1).
    12·1 answer
  • F(x)=3x-2 find each value. F(3)
    10·1 answer
  • Rectangle QRST has vertices located at Q(-9, -3), R(-1,-1), S(0,-5) and T(-8, -7). What is the length of side ST?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!