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yuradex [85]
3 years ago
13

Write an equation for the line that passes through (1, -1) and (0, -4).

Mathematics
1 answer:
Lynna [10]3 years ago
6 0
The solution to the question

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Write the equation of a line that is perpendicular to y=-2/7x+9 and passes through the point (4,-6)
Ulleksa [173]
This is in slope-intercept form, so you can think of it as being y=mx+b. Invert m (the slope) and flip its sign, and then substitute the x and y values in and solve for b. The answer is y=7/2x-20. 
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3 years ago
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Algebra help - asymptotes
motikmotik

Find where the equation is undefined ( when the denominator is equal to 0.

Since they say x = 5, replace x in the equation see which ones equal o:

5-5 = 0


So we know the denominator has to be (x-5), this now narrows it down to the first two answers.


To find the horizontal asymptote, we need to look at an equation for a rational function: R(x) = ax^n / bx^m, where n is the degree of the numerator and m is the degree of the denominator.


In the equations given neither the numerator or denominators have an exponent ( neither are raised to a power)

so the degrees would be equal.

Since they are equal the horizontal asymptote is the y-intercept, which is given as -2.


This makes the first choice the correct answer.

8 0
3 years ago
there are 12 players on the basketball roster. 9 of the players are in the 8th grade. What percent of the team is not in the 8th
alexandr402 [8]
Well there are 12 players and 9 are in 8th grade so the rest is leaving 3 so 3/12 so converted to percentage is 25% hoped this helped
3 0
2 years ago
Hiro bought a small carton of milk at lunch. If the approximate dimensions of the milk carton are shown what is the minimum amou
faltersainse [42]

Answer:

C.\ 104\ in^2

Step-by-step explanation:

At first, the question looks like an optimization problem, but since all the dimensions of the carton are given, we only have to compute the total area of the given figure.

Let's calculate the front (and back) areas, which are rectangles

A_1=(6.5)(3)=19.5\ in^2

Now with the lateral rectangles which happen to have the very same dimensions

A_2=19.5\ in^2

Next, we compute the front and back triangles of base 3 in and height 1.5 in

A_3=\frac{1}{2}(3)(1.5)=2.25\ in^2

Now, the lateral inclined rectangles of base 3 in and height 2 in

A_4=(3)(2)=6\ in^2

Finally, the base rectangle who happens to be a square of side 3 in

A_5=(3)(3)= 9\ in^2

This last area, unlike all others, is not doubled because its counterpart is inside the carton and is not part of the lateral area

Our total area of cardboard is

A_t=2(19.5)+2(19.5)+2(2.25)+2(6)+9=103.5\ in^2

The closest option to this answer is

C.\ 104\ in^2

5 0
3 years ago
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Write the product in its simplest form:
ioda

Answer:

Step-by-step explanation:

84 = 2 * 2 *3 * 7

7 0
3 years ago
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