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sesenic [268]
3 years ago
12

How do I solve this problem b+2/b-1=4/5

Mathematics
1 answer:
Gnesinka [82]3 years ago
8 0
Since this is a proportion we cross multiply.
b+2/b-1=4/5 
b-1(4)=b+2(5)
  4b-4=5b+10
    +4 = +4
     4b=5b+14
    -5b=-5b
    -1b=14
divide by -1 on both sides
b=-14
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Is the following relation a function? Two circles are shown, one labeled x and the other labeled y. The x circle contains the nu
Allushta [10]

Answer:

i  believe that it is a function.

Step-by-step explanation:

you do not have any of the exact same numbers with arrows ot one another.

5 0
3 years ago
a mower uses 5/16 gallon of gas to mow the back yard. the side yard is only 2/3 the size of the backyard. How much gas will be n
Trava [24]

Answer:

(5/24) gallons of gas to mow the side yard

Step-by-step explanation:

We can easily solve this proble by applying a rule of three

5/16 gallons of gas  ---------------------------------  for 1 backyard

x  gallons of gas ------------------------------------- 2/3 backyard

x = ((2/3)/1)*(5/16) gallons of gas

x = ((2/3))*(5/16) gallons of gas

x = ((10/48) gallons of gas

x = (5/24) gallons of gas

3 0
3 years ago
Can someone help me?
Citrus2011 [14]
If you look at the model RM is the same length as PM. PM=10 so RM=10.
3 0
2 years ago
Read 2 more answers
Solve the system of equations.<br><br><br> 2x + 3y = 1<br> y = 3x + 15
MrMuchimi
Since y=3x+15
sub 3x+15 for y in other equation

2x+3(3x+15)=1
2x+9x+45=1
minus 45
11x=-44
divide 11
x=-4

sub
y=3x+15
y=3(-4)+15
y=-12+15
y=3

(-4,3)
6 0
3 years ago
A rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet. Describe the possible lengths o
kipiarov [429]

Answer: 51.86 and 23.14

Step-by-step explanation:

The rectangular garden must have a perimeter of 150 feet

Perimeter of rectangular garden =

2l + 2w=150 -----------1

The rectangular garden must have a perimeter of 150 feet and an area of at least 1200 square feet.

Area of rectangular garden =

l×w= 1200 feet^2 -----------2

From equation 2, l=1200/w

Put l=1200/w in equation 1

2× 1200/w + 2w = 150

(2400/w) +2w = 150

(2400+2w^2)/w =150

2400+2w^2= 150w

2w^2- 150w+2400=0

Using the general formula

w = [-b+-√(b^2-4ac)]/2a

a = 2, b =-150, c=2400

w =[--150+/-√(-150^2-4×2×2400)]/2×2

=[150+/-√(22500-19200)]/4

=[150+/-√3300)]/4

=(150+57.45)/4 or (150-57.45)/4

w= 207.45/4 or 92.55/4

w= 51.86 or w= 23.14

l = 1200/51.86 or l= 1200/23.14

l = 23.14. or l= 51.86

For an area of at least 1200ft^2

The dimensions are 51.86 and 23.14

4 0
3 years ago
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