19 i think though im pretty sure it is
The average speed of Joshua during that time is 2500 m/h.
Explanation:
It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.
The total time taken by Joshua from 5:15 pm to 8:09 pm is

Dividing we get,

Adding, we have,

Thus, the total time taken by Joshua is 
To determine the average speed we use the formula,

where
and 
Hence, substituting the values we have,

Dividing, we get,

Thus, the average speed of Joshua during that time is 2500 m/h.
Answer:
10
Step-by-step explanation:

2000=1800(1.04)^t,,log(1.11)/log(1.04)=t use the calculator,,,hope it helps :-)
The total distance that was covered by the sprinter in Kilometers is:
<h3>How much is the total distance covered?</h3>
To obtain the total distance covered by the sprinter, we need to first realize that 1 Km is equal to 1000 meters. That said, the question above requires us to change 2400 meters to kilometers.
Thus we will have:
2400 Meters * 1 km / 1000 meters
= 2.4 km
So, the total distance covered by the sprinter in kilometers is 2.4
Learn more about meter conversions here:
brainly.com/question/26259781
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