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Aleks04 [339]
3 years ago
6

jared has two cakes that are the same size. The first cake was chocolate, which he cut 12 equal parts. The second cake was marbl

e, which he cut into 6 equal parts. His family eats 5 slices if chocolate cake and 3 slices of marble cake. Did they eat more chocolate cake or marble cake?
Mathematics
1 answer:
Simora [160]3 years ago
6 0

1 marble = 2 chocolate

3 marble = 6 chocolate

They only ate 5 chocolate slices so they ate more marble.

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-10 + x + 4-5 > 7x - 5
coldgirl [10]

Answer:

x < -1

Step-by-step explanation:

Step 1: Write out inequality

-10 + x + 4 - 5 > 7x - 5

Step 2: Solve

x - 6 - 5 > 7x - 5

x - 11 > 7x - 5

-11 > 6x - 5

-6 > 6x

-1 > x

Step 3: Rewrite

x < -1

3 0
3 years ago
Read 2 more answers
sarabeth is making beaded necklaces to give to five of her friends for homecoming she has 10 ft of elastic string each necklace
babunello [35]

Answer:

Yes, she has enough strong to make necklaces for five friends

Step-by-step explanation:

10 ft= 120 inches

120/20 9=in per necklace= 6

she has enough to make 6 necklaces and she only has to make five so yes

5 0
3 years ago
Help with these math exercises, please!
lions [1.4K]
1) (3-x) x (3+x)

2) 5(5-x) x (5+x)

3) (3v-wy) x (3v+wy)

4) 2(k-m) x (k+m) x (k^2+m^2)

5) (ab-4c) x (ab+4c)

Brainliest?
4 0
3 years ago
Which expression shows the factors of 9x^ +3x-2
lesya692 [45]

Answer:

\texttt{(3x+2)(3x-1)}

Step-by-step explanation:

Factors of

9x^2+3x-2

9x^2+6x-3x-2

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(3x+2)(3x-1)

6 0
2 years ago
Find the unknown length y in the following pair of the similar triangles.
yulyashka [42]

Answer:

y = 9.75

Step-by-step explanation:

Since both triangles are said to be similar, the proportion or ratio of the sides of both triangles would be equal.

Therefore, 39/y = 23/5.75 = 35/8.75

Let's find y

39/y = 23/5.75

==>Cross multiply

39*5.75 = 23*y

224.25 = 23y

==>Divide both sides by 23

224.25/23 = y

9.75 = y

y = 9.75

Check:

Thus,

39/9.75 = 23/5.75 = 35/8.75 = 4

Our answer y, which is 9.75, is correct.

5 0
3 years ago
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