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3 years ago

Instructions: Find the angle measures given the figure is a rhombus. Please Help!

Mathematics

2 answers:

nataly862011 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

since this is rhombus 1 2 3 4 must be equal

|NP|=|MN|

so 180-120=60

60/2=30

Alekssandra [29.7K]3 years ago

5 0

Answer: All four angles (angle1,2,3,4) are 30 degrees each

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Explanation:

A rhombus has all four sides that are the same length. Think of a square, but we don't necessarily need to have all four angles be 90 degrees (as the diagram indicates).

Focus on triangle MNP. We have N = 120 degrees. We also know that MN = NP due to the fact all four sides of a rhombus are the same length.

This immediately leads to triangle MNP being isosceles. The base angles opposite the congruent sides are congruent angles. So angle 1 and angle 3 are the same measure. For triangle MNP, angle M and angle P are the same.

Let's find the missing angle

M+N+P = 180 ... angles of a triangle add to 180

M+120+M = 180 ... plug in N = 120, replace P with M

2M+120 = 180

2M = 180-120 ... subtracting 120 from both sides

2M = 60

M = 60/2 .... dividing both sides by 2

M = 30

So N is also 30 degrees

------------------------

We've found that both angle 1 and angle 3 are 30 degrees each.

Any rhombus is a parallelogram, which means that angles 1 and 4 are congruent alternate interior angles. Similarly, angles 2 and 3 are the other pair of alternate interior angles.

Therefore, we can say

angle 1 = angle 4 = 30 degrees

angle 2 = angle 3 = 30 degrees

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4 years ago

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Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20

vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of $y=f(x)$ is a vertical has an asymptote at $x=a$ if at least one of the following statements is true:

$1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty$

The function is:

$f(x)=\frac{x^2+7x+10}{x^2+9x+20}$

First of all, let't factor out:

$f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq 5$

From here:

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty$

$\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty$

Accordingly:

$x=-4 \ is \ a \ vertical \ asymptote \ for \\ \\ f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20}$

<h2>Learn more:</h2>

Vertical and horizontal asymptotes: brainly.com/question/10254973

#LearnWithBrainly

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4 years ago

Gage is building a model rocket for a science fair project. He attaches a nosecone to a cylindrical body to form the rocket's fu

denpristay [2]

Answer:

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Step-by-step explanation:

The rocket has two parts: one is a cylinder and the other is a cone.

To find the total volume of the rocket, we need to find firstly the volume of each part.

The cylinder has a radius of 2 inches and a height of 2*12 + 5 - 7 = 22 inches, so its volume is:

V1 = pi * r^2 * h = pi * 2^2 * 22 = 276.46 in2

The cone has a radius of 2 inches and a height of 7 inches, so its volume is:

V2 = (1/3) * pi * r^2 * h = (1/3) * pi * 2^2 * 7 = 29.32 in2

Then, we have that the volume of the rocket is:

V = V1 + V2 = 276.46 + 29.32 = 305.78 in2

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3 years ago