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3 years ago

Can you show the steps of the answers too? pleaseeee

Mathematics

1 answer:

vaieri [72.5K]3 years ago

3 0

4(x+2) = 4·x + 4·2 = 4x + 8

3(x+7) = 3·x + 3·7 = 3x + 21

5(2x+7) = 5·2x + 5·7 = 10x + 35

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JKL is a straight line.

kirza4 [7]

Answer:

x = 32°

Step-by-step explanation:

∆KLM is an isosceles triangle because it has two equal sides, KL & KM. Therefore, the angles opposite to each of the two equal sides, which are referred to as the base angles are congruent to each other.

m<KML = m<KLM = 58°

m<MKL = 180 - (58 + 58) (Sum of triangle)

m<MKL = 64°

m<JKM = 180 - m<MKL (linear pair theorem)

m<JKM = 180 - 64 (Substitution)

m<JKM = 116°

∆JKM is also an isosceles triangle with two equal sides. Therefore, it's based angles (x & <J) would also be equal to each other.

Thus:

x = ½(180 - m<JKM)

x = ½(180 - 116) (Substitution)

x = 32°

3 0

2 years ago

I guess I'm lacking in differential equations. I couldn't solve this question. Can you help me?

Sonja [21]

Answer:

See Explanation.

General Formulas and Concepts:

Pre-Algebra

Equality Properties

Reciprocals

Algebra II

Log/Ln Property: $ln(\frac{a}{b} ) = ln(a) - ln(b)$

Calculus

Derivatives

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Derivative of Ln: $\frac{d}{dx} [ln(u)] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

$ln(\frac{2x-1}{x-1} )=t$

Step 2: Differentiate

Rewrite: $t = ln(\frac{2x-1}{x-1})$
Rewrite [Ln Properties]: $t = ln(2x-1) - ln(x - 1)$
Differentiate [Ln/Chain Rule/Basic Power Rule]: $\frac{dt}{dx} = \frac{1}{2x-1} \cdot 2 - \frac{1}{x-1} \cdot 1$
Simplify: $\frac{dt}{dx} = \frac{2}{2x-1} - \frac{1}{x-1}$
Rewrite: $\frac{dt}{dx} = \frac{2(x-1)}{(2x-1)(x-1)} - \frac{2x-1}{(2x-1)(x-1)}$
Combine: $\frac{dt}{dx} = \frac{-1}{(2x-1)(x-1)}$
Reciprocate: $\frac{dx}{dt} = -(2x-1)(x-1)$
Distribute: $\frac{dx}{dt} = (1-2x)(x-1)$

8 0

2 years ago

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Using the least common denominator rename 3/5 and 1/20

UkoKoshka [18]

LCD is 20
3/5 -> 12/20
1/20 -> 1/20

5 0

2 years ago

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The table shows the total number of student applications to universities in a particular state over a period of 12 semesters. St

ANTONII [103]

5 out of 12 = 5/12

Those are
1 - 106
2 - 137
4 - 120
6 - 195 and
8 - 139

7 0

2 years ago

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Solve the quadratic equation: 3x2 − 2x − 8 = 0

astra-53 [7]

Solutions

Factor 3x²−2x−8

1. Multiply 3 by -8, which is -24.

2. Ask: Which two numbers add up to -2 and multiply to -24?

3. Answer: 4 and -6

4. Rewrite −2x as the sum of 4x and −6x:

$3x^2+4x-6x-8=0$ 

Factor out common terms in the first two terms, then in the last two terms

$x(3x+4)-2(3x+4)=0

 
$

Factor out the common term 3x+4

 $(3x+4)(x-2)=0$

Solve for x

1. Ask: When will (3x+4)(x−2) equal zero?

2. Answer: When 3x+4=0 or x−2=0.

3. Solve each of the 2 equations above:

x = −4 / 3,2

8 0

3 years ago

Read 2 more answers