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Keith_Richards [23]
3 years ago
6

0. 00147 in standard form

Mathematics
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

Answer: It can be written as 1.47x10-³

Step-by-step explanation:

0.00147 = 1.47

1.47 = 1.47 x 10 -^3

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Help me please will give a lot of points answer all of them
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Step-by-step explanation:

i like pizza and ice cream

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4 years ago
Can rational numbers include negative and positive numbers? or can there only be positive numbers?
lions [1.4K]
Both negative & positive
3 0
4 years ago
Kristen gets home from work at 5:34pm Kristen's dinner is ready at 5:51pm How many seconds after Kristen gets home is her dinner
alina1380 [7]

Answer:

1020 seconds

Step-by-step explanation:

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times that by 60 to get seconds and its 1020

3 0
4 years ago
Read 2 more answers
How do I find the Velocity and How long will it take for the ball to reach it's maximum height?
Colt1911 [192]
So hmm check the picture below

\bf \qquad \textit{initial velocity}\\\\
h = -16t^2+v_ot+h_o \qquad \text{in feet}\\
\\ 
\begin{cases}
v_o=\textit{initial velocity of the object}\to &64\\
h_o=\textit{initial height of the object}\to &12\\
h=\textit{height of the object at "t" seconds} \end{cases}\\\\
-----------------------------\\\\

\bf \textit{vertex of a parabola}\\ \quad \\

\begin{array}{lccclll}
h(t)=&-16t^2&+64t&+12\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)

part 1)  

it takes  \bf -\cfrac{{{ b}}}{2{{ a}}}\quad seconds

part 2)

\bf \textit{now, doubling }v_o\\\\
\begin{cases}
v_o=\textit{initial velocity of the object}\to &128\\
h_o=\textit{initial height of the object}\to &12\\
h=\textit{height of the object at "t" seconds}\end{cases}\\\\
-----------------------------\\\\
\textit{vertex of a parabola}\\ \quad \\

\begin{array}{lccclll}
h(t)=&-16t^2&+128t&+12\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array}\qquad 
\left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad  {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right)

it will reach the maximum height at   \bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\quad feet


how much higher than before is that? well, what was the y-coordinate for when the vₒ was 64? what did you get for \bf {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}} ?

subtract that from this height when vₒ is 128 or doubled, to get their difference, that's how much higher it became

4 0
3 years ago
Round 5,762.384 to the nearest ten
swat32
If it's nearest ten then it would be 5,760. If anything is 4 or lower than the number, like 74, then it would be 70. 
If it was 5 or higher, like 37, then it would become 40.
Hope this helps! :) 
7 0
3 years ago
Read 2 more answers
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