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3 years ago

Given g(x)=9x^2-5 and k(x) =3x-1, find g(x) + k(x)

Mathematics

2 answers:

Sphinxa [80]3 years ago

8 0

I hope this helps you

Question wants sum of two functions

g(x) +k(x)

9x^2-5+3x-1

9x^2+3x-6

3(3x^2+x-2)

3(3x-2)(x+1)

diamong [38]3 years ago

5 0

A because I need 5 points

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Simplify -7(-4p+1) + 2p

mariarad [96]

Step-by-step explanation:

-7(-4p+1) + 2p

-7 x -4 = 28p

-7 x 1 = -7

28p + 2p = 30p

30p-7

8 0

3 years ago

Kevin ran at a rate of 13km/h convert his speed to meter minute

goldfiish [28.3K]

1 hour = 60 minutes

13/60 = 0.2

answer: 0.2m/min

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3 years ago

Solve the following initial-value problem: (ex+y)dx+(3+x+yey)dy=0, y(0)=1 0=

alex41 [277]

Answer:

$e^x+xy+3y+(y-1)e^y=4$

Step-by-step explanation:

Given that

$(e^x+y)dx+(3+x+ye^y)dy=0$

Here

$M=e^x+y$

$N=3+x+ye^y$

We know that

M dx + N dy=0 will be exact if

$\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$

$\frac{\partial N}{\partial x}=1$

it means that this is a exact equation.

$\int d\left(e^x+xy+3y+(y-1)e^y\right)=0$

Noe by integrating above equation

$e^x+xy+3y+(y-1)e^y=C$

Given that

x= 0 then y= 1

$e^0+0+3+(1-1)e^1=C$

C=4

So the our final equation will be

$e^x+xy+3y+(y-1)e^y=4$

3 0

3 years ago

2s+10-7s-8+3s-7 syplifying expression fyi

Solnce55 [7]

Answer:

-1+5z, -25+20y, 4d+14, 2n-2, 40k+8, 8b+5, -9+22p

Step-by-step explanation:

1) -4+7z+3-2z

-1+5z

2) 15+4(5y-10)

15+20y-40

-25+20y

3) 2d+17-3-2d+4d

4d+14

4) 12n-8-2n+10-4

2n-2

5) 8(2k+1+3k)

16k+8+24k

40k+8

5) 4(2b+2)-3

8b+8-3

8b+5

6) -4+8p-6p-5+20p

-9+22p

7 0

3 years ago

How do you do question 22

Alborosie

Answer:

∠YXZ = 58°

Step-by-step explanation:

Use the angle sum theorem and the given relations.

∠WXY +∠WXV = ∠YXV

∠WXY +(11° +3∠WXY) = 139°

4∠WXY = 128° . . . . . subtract 11°

∠WXY = 32° . . . . . . . divide by 4

Similarly, ...

∠WXY +∠YXZ = 90°

∠YXZ = 90° -∠WXY = 90° -32°

∠YXZ = 58°

6 0

3 years ago