Answer:
m∠1 = 60°
m∠2 = m∠4 = 39°
m∠3 = m∠5 = 21°
Step-by-step explanation:
ΔWXY is a equilateral angle,
Therefore, all angles of the the triangle are equal in measure.
m∠W + m∠X + m∠Y = 180°
3m∠W = 180°
m∠W = 60°
Since, ΔWZY is an isosceles triangle,
m∠3 = m∠5
m∠3 + m∠Z + m∠5 = 180°
m∠3 + 138° + m∠3 = 180°
2m∠3 = 180 - 138
m∠3 = 21°
Therefore, m∠3 = m∠5 = 21°
Since, m∠2 + m∠3 = 60°
m∠2 = 60 - 21
= 39°
Since, m∠4 + m∠5 = 60°
m∠4 = 60 - 21
= 39°
m∠1 = 60°
8 is a whole number, so this will be the whole number part of our mixed number.
0.25 is a decimal, where 25 is in the HUNDREDths place, so we write 25 as a fraction over 100.

Simplify by dividing 25 to the numerator and denominator.


So our fraction is

0.55 is a decimal, where 55 is in the HUNDREDths place, so we write 55 as a fraction over 100.

Simplify by dividing 5 to the numerator and denominator.


So our fraction is


To convert this to a decimal, just divide 5 / 8
Answer:
The minimum score a person must have to qualify for the society is 162.05
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
Test scores are normally distributed with a mean of 140 and a standard deviation of 15. This means that
.
What is the minimum score a person must have to qualify for the society?
Since the person must score in the upper 7% of the population, this is the X when Z has a pvalue of 0.93.
This is
.
So




The minimum score a person must have to qualify for the society is 162.05