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DaniilM [7]
3 years ago
6

suppose the commute times for employees of a large company follow a normal distribution. if the mean time is 18 minutes and the

standard deviation is 5 minutes, 95% of the employees will have a travel time within which range A. 13 mins to 23 mins B. 3 mins to 33 mins c 8mins to 28 mins D 13.25 and 22.75
Mathematics
2 answers:
Oksanka [162]3 years ago
6 0

Answer: 8 minutes to 28 minutes

Step-by-step explanation:

To include 95% of all employees, it will be 2 standard deviations from the mean. Two above and two below. Each is 5 min. So add 10 and subtract 10 from 18.

On the Gaussian Curve, about 68.3% are included within the first standard deviation above and below the mean. Then about 27.2% are added in the second standard deviation.

stepladder [879]3 years ago
4 0

Answer:I think A

Step-by-step explanation:

Hopefully I am right

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Organisers for a charity event sold 500 tickets. Adult price £3 and children £2. Money received from adult ticket sales is £400
Tatiana [17]

Answer: 280

<u>Step-by-step explanation:</u>

                  Quantity   X    Cost    =  Money Received

Adult:               x                   3                   3x          

Children:       500-x              2            2(500 - x) = 1000 - 2x


Adult = Children + 400

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7 0
3 years ago
Pls pls pls help <br>Find the perimeter and the area​
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
A) 20 milligrams of the drug lincomycin is to be given for each kilogram of a person's weight the drug is be mixed with 250 cc o
krok68 [10]

Answer:

you need to convert pounds to kilograms. 196 pounds is 88.904 kilograms. The directions tell you that 20 milligrams of the drug is to be administered for each kilogram of a person's weight. Now you need to multiply 88.904 by 20. That should give you 1778.08 milligrams of lincomycin. You would then mix 250 cc's of saline solution to the 1778.08 milligrams of lincomycin; but I think its just asking you how much lincomycin to administer.

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4 0
3 years ago
Which is equivalent to 64 Superscript one-fourth?
Schach [20]

Answer:

2 RootIndex 4 StartRoot 4 EndRoot

Step-by-step explanation:

we have

64^{\frac{1}{4}}

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64=2^{6}=2^{4}2^{2}

substitute

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7 0
3 years ago
Read 2 more answers
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