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2 years ago

3/4 foot =___inches Fill in the Blank

Mathematics

2 answers:

MrMuchimi2 years ago

8 0

The answer is 9 inches

vova2212 [387]2 years ago

6 0

9 inches, I think, hope this helps

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PLEASE HELP IM BEGGING!!!!

IRISSAK [1]

Answer:

y = 28°

Step-by-step explanation:

The triangle is a right triangle which has 90 degrees.

The 3x falls under 90 degrees.

So:

→ 2y + 90° + 34° = 180°

→ 2y = 180° - 124°

→ 2y = 56°

→ y = 28°

5 0

2 years ago

Read 2 more answers

15 points: can someone help me with this thank you. (all separate equations)

OLga [1]

Step-by-step explanation:

$6x+3y=12\qquad\text{subtract}\ 6x\ \text{from both sides}\\\\6x-6x+3y=12-6x\\\\3y=12-6x\qquad\text{divide both sides by 3}\\\\\dfrac{3y}{3}=\dfrac{12}{3}-\dfrac{6y}{3}\\\\\large\boxed{y=4-2y}\\\\===================$

$2p-k=3\qquad\text{subtract}\ 2p\ \text{from both sides}\\\\2p-2p-k=3-2p\\\\-k=3-2p\qquad\text{change the signs}\\\\k=-3+2p\\\\\large\boxed{k=2p-3}\\\\===================$

$6v-2w=10\qquad\text{subtract}\ 6v\ \text{from both sides}\\\\6v-6v-2w=10\\\\-2w=10-6v\qquad\text{divide both sides by (-2)}\\\\\dfrac{-2w}{-2}=\dfrac{10}{-2}-\dfrac{6v}{-2}\\\\w=-5+3v\\\\\large\boxed{w=3v-5}\\\\===================$

5 0

2 years ago

What's 468 to the 50 power

kykrilka [37]

i tried 2 different calculators and 3 different calculators the three online said the same answer whish is this 3.253064e+133 and my two calculators both said error try again literally but your answer is

5 0

3 years ago

Read 2 more answers

For the differential equations dydx=sqrt(y^2−36) does the existence/uniqueness theorem guarantee that there is a solution to thi

julsineya [31]

Answer:

1. (-4,6) there is no a solution to the equation through this point

2. (2,−6) there is no a solution to the equation through this point

3. (−5,39) there is a solution to the equation through this point

4. (−1,45) there is a solution to the equation through this point

Step-by-step explanation:

Using the existence and uniqueness theorem:

Let:

$F(x,y)=\sqrt{y^2-36} \\\\and\\\\\frac{\partial F}{\partial y} =\frac{y}{\sqrt{y^2-36} }$

Now, let's find the domain of $F(x,y)$ , due to the square root:

$y^2-36 \geq 0\\\\y^2\geq 36\\\\y \geq 6\hspace{12}or\hspace{12}y\leq-6$

So the domain of the function is:

$y \in R\hspace{12}y\geq6\hspace{12}or\hspace{12}y\leq-6$

Now, due to the fraction $\frac{\partial F}{\partial y}$ the denominator must be also different from 0, so:

$y^2-36\neq0\\\\y \neq \pm6$

So, the theorem tells us that for each $y_0\in R:\hspace{12}y_0>6\hspace{12}or\hspace{12}y_0$ there exists a unique solution defined in an open interval around $x_0$ .