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3 years ago

5

Mona is skating at a speed of 300 feet per minute. Lina is 1000 feet behind her. What should be her speed if she wants to catch

up with Mona in 10 minutes?

1 answer:

Allisa [31]3 years ago

4 0

If we translate the facts into location equations, xM=Mona's location, xL=Lina's location, then we get:

xM(t) = 300t
xL(t) = v*t - 1000
xM(10)=xL(10)

Where v is Lina's speed we have to find.

Plugging them all together gives:

300*10 = 10v - 1000

Which can be solved:

3000 + 1000 = 10v
4000 = 10v
v=400

Lina should skate at 400 feet per minute!

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4 years ago

Read 2 more answers

The sides OP and RO of triangle POR are produced to points S and T respectively. If ∠SPR = 145° and ∠POT = 115° , find ∠PRO

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Answer:

$\angle PRQ = 80$

Step-by-step explanation:

Given

$\angle SPR = 145^o$

$\angle POT = 115^o$

See attachment

Required

Find $\angle PRO$

First, calculate $\angle RPO$

$\angle RPO + \angle SPR = 180$ --- angle on a straight line

So, we have:

$\angle RPO + 145 = 180$

Collect like terms

$\angle RPO = 180 - 145$

$\angle RPO = 35$

Next, calculate PQR

$\angle POR + \angle POT = 180$

So, we have:

$\angle POR + 115 = 180$

Collect like terms

$\angle POR = 180-115$

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So, PRO is calculated as:

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So, we have:

$\angle PRO + 65 + 35= 180$

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Collect like terms

$\angle PRO = 180-100$

$\angle PRO = 80$

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