Answer is C because it is proportion.
Answer:
R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Step-by-step explanation:
Squaring both sides of equation:
I^2 = (ER)^2/(R^2 + (WL)^2)
<=>(ER)^2 = (I^2)*(R^2 + (WL)^2)
<=>(ER)^2 - (IR)^2 = (IWL)^2
<=> R^2(E^2 - I^2) = (IWL)^2
<=> R^2 = (IWL)^2/(E^2 - I^2)
<=> R = sqrt[(IWL)^2/(E^2 - I^2)] or R = -sqrt[(IWL)^2/(E^2 - I^2)]
Hope this helps!
Answer:
x=7
y=9
Step-by-step explanation:
x+7y=70 ...(1)
3x-6y=-33
divide by 3
x-2y=-11 ...(2)
(1)-(2) gives
x+7y-x+2y=70+11
9y=81
y=9
x-2*9=-11
or x=-11+18=7